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hodyreva [135]
2 years ago
8

the penguin nursery is open two times a day 2/3 hour at noon and 5/12 hour in the afternoon.How much time is the penguin nursery

open every day?​
Mathematics
1 answer:
KonstantinChe [14]2 years ago
7 0
2/3x4/4= 8/12
8/12+5/12=13/12
=1 1/12 hours
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Initially, a population of rabbits was found to contain 192 rabbits. It was estimated that the population was growing exponentia
aleksley [76]

Answer:

the population after 52 days is $34,804.27

Step-by-step explanation:

Given that

There is a population of the rabbits i.e. 192

And, the growth rate is 10%

We need to find out the population after 52 days

So,

= 192 × e^(0.10 × 52)

= $34,804.27

hence, the population after 52 days is $34,804.27

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2 years ago
Help pleaseeee ??????!!!!! I choosed the Death Valley one
disa [49]
1.) C(t) = -0.30(t - 12)^2 + 40
for t = 12: C(12) = -0.30(12 - 12)^2 + 40 = -0.30(0)^2 + 40 = 40°C
For t = 24: C(24) = -0.30(24 - 12)^2 + 40 = -0.30(24 - 12)^2 + 40 = -0.30(12)^2 + 40 = -0.30(144) + 40 = -43.2 + 40 = -3.2°C

4.) F(t) = 9/5 C(t) + 32
for C(t) = 40°C: 9/5 (40) + 32 = 72 + 32 = 104°F
for C(t) = -3.2°C: 9/5(-3.2) + 32 = -5.76 + 32 = 26.24°F

5.) F(t) = 9/5 C(t) + 32 = 9/5 (-0.30(t - 12)^2 + 40) + 32 = -0.54(t - 12)^2 + 72 + 32 = -0.54(t - 12)^2 + 104
5 0
3 years ago
What is 4 + 15 × 7 =
il63 [147K]

Answer:

109

Step-by-step explanation:

4 + 15 \times 7  \\  = 4 + 105 \\  = 109

5 0
3 years ago
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Which is a correct step in solving the following equation for g?
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3 years ago
Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil
andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that p = 0.26

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that n = 5

4 failures, so 1 success, and we have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898

0.3898 = 38.98% probability that there will be 4 failures

4 0
3 years ago
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