Given:
u(initial velocity)=0
a=5.54m/s^2
v(final velocity)=2 m/s
v=u +at
Where v is the final velocity.
u is the initial velocity
a is the acceleration.
t is the time
2=0+5.54t
t=2/5.54
t=0.36 sec
Answer:
1 / f = 1 / p + 1 / q
Explanation:
For this exercise we will use two methods, an analytical method which is to use the constructor equation
1 / f = 1 / p + 1 / q
where f is the focal length, positive for converging lenses and negative for diverging lenses, p and q are the distance to the object and the image respectively
m = h’/ h = - q / p
where m is the magnification, h ’and h are the height of the image and the object.
We will also use a graphical method, where three rays will be traded
1) A ray that passes through the center of the lens and should not
2) a ray that passes through the focal length and comes out parallel to the lens
3) A ray that is horizontal and comes out through the focal from the other side
for this second method see the attachment
Cumulus? They are fluffy clouds that have flat bottoms. Is this what you need?
Im not sure but i guess you should try A