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3 years ago

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Two billiard balls (each with mass equal to 170 g) collide head-on along the same line. Billiard ball A originally traveled east

ward at 8 m/s while billiard ball B originally traveled westward at 2 m/s. Calculate the speed and direction of each ball after the collision.

1 answer:

barxatty [35]3 years ago

5 0

Answer:

lucky mauld mauldgomary was an british poet...

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Question 2 (1 point)

eduard

Answer: Blake may have a decreased chance of disease.

Explanation:

Research has shown that on average, a person who engages in more physical activity will live longer than a person who does not with one reason for this being that engaging in physical activity helps reduce the risk of diseases such as; heart disease, diabetes, and many forms of cancer.

Obesity (risk factor) and high blood pressure are also reduced by engaging in physical activity.

6 0

3 years ago

What is the moment of inertia of an object that rolls without slipping down a 3.5-m- high incline starting from rest, and has a

Daniel [21]

Answer:

I = 0.287 MR²

Explanation:

given,

height of the object = 3.5 m

initial velocity = 0 m/s

final velocity = 7.3 m/s

moment of inertia = ?

Using total conservation of mechanical energy

change in potential energy will be equal to change in KE (rotational) and KE(transnational)

PE = KE(transnational) + KE (rotational)

$mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2$

v = r ω

$mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{Iv^2}{r^2}$

$I = \dfrac{m(2gh - v^2)r^2}{v^2}$

$I = \dfrac{mr^2(2\times 9.8 \times 3.5 - 7.3^2)}{7.3^2}$

$I =mr^2(0.287)$

I = 0.287 MR²

3 0

4 years ago

our lab partner wears a new pair of sneakers to lab and, rather than performing the required experiments, you decide to measure

Dafna1 [17]

Answer:

The coefficient of static friction between your partner and the floor is 0.55

Explanation:

Given:

Mass $m = 59$ Kg

Frictional force $F_{s} = 318.3$ N

From the formula of frictional force,

$F_{s} = \mu_{s} mg$

Where $\mu _{s} =$ coefficient of static friction, $g = 9.8 \frac{m}{s^{2} }$

Put the above values and find the coefficient of static friction.

$318.3 = \mu_{s} \times 59 \times 9.8$

$\mu_{s} = 0.55$

Therefore, the coefficient of static friction between your partner and the floor is 0.55

4 0

3 years ago

A person slaps her leg with her hand, bringing her hand to rest in 2.50 milliseconds from an initial speed of 4.00 m/s.

gtnhenbr [62]

Answer:

(a) 2400N

(b) Yes

Explanation:

(a) Mass (m) = 1.5kg, initial speed (v) = 4m/s, time (t) = 2.5milliseconds = 2.5/1000 = 0.0025seconds

F = mv/t = (1.5×4)/0.0025 = 6/0.0025 = 2400N

(b) The force would be different because the mass of the two hands and forearms is 3kg (2 × 1.5kg = 3kg)

4 0

3 years ago

On earth a 2.25 kg object is lifted a height of 5.22m. What is the gravitational potential energy

zysi [14]

Answer:

<h2>117.45 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 2.25 × 10 × 5.22

We have the final answer as

<h3>117.45 J</h3>

Hope this helps you

8 0

3 years ago