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HACTEHA [7]
2 years ago
7

Two billiard balls (each with mass equal to 170 g) collide head-on along the same line. Billiard ball A originally traveled east

ward at 8 m/s while billiard ball B originally traveled westward at 2 m/s. Calculate the speed and direction of each ball after the collision.
Physics
1 answer:
barxatty [35]2 years ago
5 0

Answer:

lucky mauld mauldgomary was an british poet...

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Which statement best describes the relationship between atoms and nuclear forces? (2 points)
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D. Strong nuclear forces hold the nucleus of an atom together. Weak nuclear forces are involved when certain types of atoms break down.

Explanation:

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Which of the following will most likely be a sustainable environment?
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I think A

Explanation:

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A railroad car having a mass of 15 Mg is coasting at 1.5 m/s on a horizontal track. At the same time another car having a mass o
luda_lava [24]

Answer:

Explanation:

We shall apply law of conservation of momentum to know velocity after collision . Let it be v .

total momentum before collision = total momentum after collision

15 x 1.5 - 12 x .75 = ( 15 + 12 ) v

v = .5 m /s

kinetic energy before collision

1/2 x 15 x 1.5² + 1/2 x 12 x .75²

= 16.875 + 3.375

= 20.25 J

kinetic energy after collision

= 1/2 x ( 15 + 12 ) x .5²

= 3.375 J

Loss of energy = 16.875 J

This energy appear as heat and sound energy that is produced during collision .

4 0
3 years ago
A cat is shot horizontally out of a cannon that is on top of a 125 meter tall cliff. If the cat lands 286 m away from the base o
Elden [556K]

The initial velocity of the cat is 56.6 m/s

Explanation:

The motion of the cat is a projectile motion, consisting of:

- a uniform horizontal motion with constant velocity

- a vertical accelerated motion with constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:

s=ut+\frac{1}{2}at^2

where we have (choosing downard as positive direction)

s = 125 m is the vertical displacement of the cat

u = 0 is the initial vertical velocity

t is the time taken to reach the ground

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(125)}{9.8}}=5.05 s

Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by

v_x =\frac{d}{t}

where

d = 286 m is the horizontal distance travelled

t = 5.05 s is the time taken

Solving the equation,

v_x = \frac{286}{5.05}=56.6 m/s

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0
3 years ago
2. The force between charges is 7 N. The distance between the charges is 4 x 10-6 m. If one of the charges is 2 x 10-8 C, what i
g100num [7]

Answer:

2) 6.22 × 10^-13

3) 4.56 × 10^-4

Explanation:

4 0
2 years ago
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