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Brilliant_brown [7]
1 year ago
8

Use the given information to find the unknown value:y varies inversely with a. When x = 4, then y= 4. Find y when I = 2.Iyy =hel

p (numbers)

Mathematics
1 answer:
Mashutka [201]1 year ago
3 0

Inverse variation:

y=\frac{k}{x}

k is a constant

Use the given information (when x=4 y=4) to find the value of the constant:

\begin{gathered} 4=\frac{k}{4} \\  \\ \text{Multiply both sides of the equation by 4:} \\ 4\times4=4\times\frac{k}{4} \\  \\ 16=k \\  \\  \\ k=16 \end{gathered}

Then, the given relationship has the next equation:

y=\frac{16}{x}

Use the equation above to find y when x=2:

\begin{gathered} y=\frac{16}{2} \\  \\ y=8 \end{gathered}Then, when x=2, y=8
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Step-by-step explanation:

Given

n(U) = 12

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Required

Solve a, b and c

There are several ways to solve this; the best is by using Venn diagram (see attachment for diagram)

Solving (a):

n(A\ u\ B)

This is calculated as:

n(A\ u\ B) = n(A) + n(B) - n(A\ n\ B)

From the attachment

n(A) = 0+2+4+2 = 8

n(B) = 0+2+4+2 = 8

n(A\ n\ B) = 4 +2 = 6

So:

n(A\ u\ B) = 8 + 8 - 6

n(A\ u\ B) = 10

Solving (b):

n(A'\ u\ C)

This is calculated as:

n(A'\ u\ C) = n(A') + n(C) -n(A'\ n\ C)

From the attachment

n(A) = n(U) - n(A) = 12 - 8 = 4

n(C) = 0+2+4+2 = 8

n(A'\ n\ C) = 2

So:

n(A'\ u\ C) = 4 + 8 - 2

n(A'\ u\ C) = 10

Solving (c):

n(A\ n\ B)'

This is calculated as:

n(A\ n\ B)' = n(U) - n(A\ n\ B)

n(A\ n\ B)' = 12- 6

n(A\ n\ B)' = 6

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