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masha68 [24]
2 years ago
14

Please help me, I’ll mark your answer as brainliest!

Mathematics
1 answer:
wlad13 [49]2 years ago
7 0

Answer:

question 1

y= 2x+13

question 2

y= 2x +13?

TBH I'm not sure

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Daron purchased a cell phone case from the corner store. Daron paid with a $20 bill. The picture to the left shows his change. H
svlad2 [7]
Do you have a picture of the question
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3 years ago
Find the quotient. -10d 4e3f 5 ÷ 15d 2e 2f
ruslelena [56]
<span>2/3d2ef5 i believe, hope it helps

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8 0
3 years ago
Jim is saving nickels, dimes and quarters to buy a baseball mitt. He has 12 more
Harrizon [31]

Answer:

36 quarters   48 dimes  64 nickels

Step-by-step explanation:

quarter = q

dime = q+12

nickel = 2q-8

$17 = 1,700 cents

(q)25 + (q+12)10 + (2q-8)5 = 1,700

25q +10q+120  +10q-40 =1,700

45q+80 = 1,700

45q = 1620

q= 36      

 36     QUARTERS x25 =  900cents

 48 DIMES    x10      =         480 cents

  64 NICKELS x 5 =             320 cents

  TOTAL                              1,700 cents ($17)

5 0
2 years ago
Jane was paid $316 for 40 hours of work. Use compatible numbers to find about how much
Vinvika [58]

Answer:

$7.9 /hour

Step-by-step explanation:

$316/40 = $7. 9per hour

4 0
3 years ago
If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
2 years ago
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