Answer:
18x-5≤-45
Step-by-step explanation:
Let
x--------> the time in minutes
y-------> an altitude in feet
we know that
For x=0 min y=0 ft
For x=50 min y=52,000 ft
so
the rate of change is equal to calculate the slope of the linear equation
![\frac{52,000-0}{50-0}=\frac{52,000}{50}=1,040\frac{ft}{min}](https://tex.z-dn.net/?f=%5Cfrac%7B52%2C000-0%7D%7B50-0%7D%3D%5Cfrac%7B52%2C000%7D%7B50%7D%3D1%2C040%5Cfrac%7Bft%7D%7Bmin%7D)
Round to the nearest hundred-------->
therefore
<u>the answer is</u>
![1,000\frac{ft}{min}](https://tex.z-dn.net/?f=1%2C000%5Cfrac%7Bft%7D%7Bmin%7D)
L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
![\frac{-b+/- \sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-b%2B%2F-%20%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%20)
we got
a=1
b=6
c=-50
W=
![\frac{-(6)+/- \sqrt{(6)^2-4(1)(-50)} }{2(1)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-%286%29%2B%2F-%20%5Csqrt%7B%286%29%5E2-4%281%29%28-50%29%7D%20%7D%7B2%281%29%7D%20)
W=
![\frac{-6+/- \sqrt{36+200} }{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-6%2B%2F-%20%5Csqrt%7B36%2B200%7D%20%7D%7B2%7D%20)
W=
![\frac{-6+/- \sqrt{236} }{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-6%2B%2F-%20%5Csqrt%7B236%7D%20%7D%7B2%7D%20)
W=
![\frac{-6+/- 2\sqrt{59} }{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-6%2B%2F-%202%5Csqrt%7B59%7D%20%7D%7B2%7D%20)
W=
![-3+/- \sqrt{59}](https://tex.z-dn.net/?f=%20-3%2B%2F-%20%5Csqrt%7B59%7D%20%20)
W=
![-3+ \sqrt{59}](https://tex.z-dn.net/?f=%20-3%2B%20%5Csqrt%7B59%7D%20%20)
or W=
![-3- \sqrt{59}](https://tex.z-dn.net/?f=%20-3-%20%5Csqrt%7B59%7D%20%20)
aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59
It shows three periods of a sin graph