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just olya [345]
3 years ago
8

At a sale at an electronics store, a plasma television originally priced at $500 is marked 15% off. What is its selling price.​

Mathematics
1 answer:
Liula [17]3 years ago
4 0

Answer:Selling price is 425

Step-by-step explanation:

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Step-by-step explanation:

Penis

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Would the graph of the following function be discrete or continuous? <br><br> y = 15 + 3x
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If n is the term, what is the first integer value of n where the sequence 2n² is greater than 50?
Nezavi [6.7K]

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The 6th term is first integer value of n greater then 50 in the 2n^2 sequence.

Step-by-step explanation:

2n^2 sequence:

2,8,18,32,50,72

3 0
3 years ago
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0
3 years ago
Hi if you know this pls answer it thank you!!
adelina 88 [10]

Answer: it is b

Step-by-step explanation: just count how many lines between x and x' to the right its positive to the left its negative

8 0
2 years ago
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