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3 years ago

A circle is placed in a square with a side length of 10 mm, as shown below. Find the area of the shaded region.

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

7 0

Answer:

21.5

Step-by-step explanation:

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The question <br> Najheheggebbsbv nhsygenbs

dezoksy [38]

Answer: 1.) √121= 11

Step-by-step explanation:

11•11=121

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3 years ago

A music school offers its students 8 different classes each semester. 4 of the classes are in music theory, 3 of the classes are

Bond [772]

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2 years ago

Solve a^3 • (-a^2b)^4

Varvara68 [4.7K]

Answer:/?idk

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3 years ago

SOLVE FOR M. please :)

STatiana [176]

Answer:

$m = - 28$

Step-by-step explanation:

$\frac{ - 3}{7} m = 12$

$\frac{ - 7}{3} ( \frac{ - 3}{7})m = \frac{ - 7}{3} \times 12$

$\frac{ - 1}{3} ( - 3)m = \frac{ - 7}{3} \times 12$

$- 1( - 1)m = \frac{ - 7}{3} \times 12$

$1 \times m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} (3 \times 4)$

$m = - 28$

<h3>Hope it is helpful....</h3>

3 0

3 years ago

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?

zubka84 [21]

$H(x)=(x^2)+1\ \ \ \ and\ \ \ \ K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.$

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2 years ago