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Mila [183]
3 years ago
8

Can anyone answer this? I need help ASAP!!

Mathematics
1 answer:
laiz [17]3 years ago
8 0

Answer: y = 3/5x -5, y=3/5x + - 5

Step-by-step explanation:

Slope = Rise/run

intersect is at -5

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galben [10]

Answer:

y=2.50+3.25x,

Step-by-step explanation:

because

7 0
3 years ago
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Skylar plans to use $3400 to open a savings account with an annual interest rate of 1.15%. How much more interest will he earn o
Tanzania [10]

Answer:

$ 2.5

Step-by-step explanation:

Given that

Total Amount to be invested = P = $3400

Total Time of investment = t = 13 years

Rate of interest = r = 1.15 %

Lets calculate Simple interest first

As we know formula for simple interest is

A = P (1 +r)^{t}

Substituting the values

A = 3400(1+ \frac{1.15}{100} )^{13}

A =  $ 3944.9

Lets now calculate the compound interest

As we know formula for simple interest is

A = P (1 + \frac{r}{n})^{nt}

 As compound interest applies every 3 months so n =3

So,

A = 3400 (1 + \frac{1.15}{100*4} )^{13*4}

A  = $ 3947.4

Now Lets calculate how much more he will earn using compound interest.

It can be found by taking difference of compound interest and simple interest

Amount = 3947.4 - 3944.9 = $ 2.5

So Skyler must have earned 2.5 dollar more using the compound interest.

8 0
3 years ago
If you are dividing a whole number by a fraction you must first do what to the whole number?
Sladkaya [172]

Answer:

Multiply the whole number by the denominator of the fraction.

90 / 1/10 = 900Step-by-step explanation:

8 0
3 years ago
How to solve an expression with variables in the exponents?
gtnhenbr [62]

Answer:

  use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

__

You will note that this approach works well enough for ...

  a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

  (x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

  x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0
3 years ago
Triclosan is a compound often added to products such as soaps, lotions, and toothpaste. It is antimicrobial, so for that reason,
miv72 [106K]

Answer:

The appropriate alternative hypothesis is, <em>Hₐ</em>: <em>p</em>₁ - <em>p</em>₂ > 0.

Step-by-step explanation:

In this case it is provided that Triclosan is a compound often added to products such as soaps, lotions, and toothpaste.

Since the compound is antimicrobial its corporate producer maintained that it should help prevent staph infections among people who use products containing the compound.

But a scientist wants to test whether the compound actually is associated with higher incidence of staph infection.

That is he wants to determine whether people with a detectable level of triclosan have higher rates of carrying the staph bacteria than people without triclosan.

Denote:

<u>Group 1:</u> people with a detectable level of triclosan

<u>Group 2:</u> people without a detectable level of triclosan

To test this the hypothesis can be defined as follows:

<em>H₀</em>: The proportion of people with a detectable level of triclosan does not have higher rates of carrying the staph bacteria than people without triclosan, i.e. <em>p</em>₁ - <em>p</em>₂ ≤ 0.

<em>Hₐ</em>: The proportion of people with a detectable level of triclosan have higher rates of carrying the staph bacteria than people without triclosan, i.e. <em>p</em>₁ - <em>p</em>₂ > 0.

Thus, the appropriate alternative hypothesis is, <em>Hₐ</em>: <em>p</em>₁ - <em>p</em>₂ > 0.

6 0
3 years ago
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