An amusement park employee records the ages of the people who ride the new roller coaster during a fifteen-minute period.

About 57 people rent skates at the skating rink each day. It cost $4.25 to rent skates. About how much does the Rink make in ska

seraphim [82]

Answer:1695.75

Step-by-step explanation:

We know that there are 7 days in a week. Since 57 people rent skates each day, we know that 57*7=399 skates are rented each week. Since one skate cost 4.25, we know that 399*4.25 is the cost, which is 1695.75. (If you are not allowed to use a calculator, you can do 400*4.25-4.25, to make it easier to compute)

4 0

3 years ago

What is the x-coordinate of point B? A -1 B - 4 С 1 D 4

Dmitry_Shevchenko [17]

The x-coordinate would be -4 which would be answer choice B. This is the reason bc when you look at a graph it goes from x to y same as the alphabet

5 0

3 years ago

Read 2 more answers

Math help please show work

saw5 [17]

Answer:

You can measure the area of the yard but measuring the length and width and then multiplying. Then you can divide by the amount of sod that is used to cover to see how many bags that need to be bought.

Step-by-step explanation:

This should be good :)

pls mark brainliest:)

3 0

3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.