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2 years ago

HELPPP MY MATH HOMEWORK!!!

Mathematics

2 answers:

11Alexandr11 [23.1K]2 years ago

7 0

D and then A I would say

statuscvo [17]2 years ago

7 0

I dont know how to answer number 12 but number 13 is the first one 3x + 15 = 17

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Which expression shows the prime factorization of 100

aliina [53]

100 = 10 × 10
100 = 2 × 5 × 2 × 5

100 = 2² × 5²

The prime factorization of 100 is 2² × 5².

8 0

3 years ago

Plato Necessities produces camera cases. they have found that the cost, c (x), of making x camera cases is a quadratic function

Phoenix [80]

This answer has been deleted.

3 0

3 years ago

Anna has 196 pepper plants that she wants to plant in a square formation how many pepper plants should she plant in each row

skad [1K]

She should plant 14 plants in each row

Step-by-step explanation:

Given

Total pepper plants = 196

As the plants have to be in square shape, the number of rows and the plants in each row will be equal

Let x be the number of rows

Then

$x^2 = 196\\$

Taking square root on both sides

$\sqrt{x^2} = \sqrt{196}\\x = 14$

Hence,

She should plant 14 plants in each row

Keywords: Square root, Radicals

Learn more about square root at:

#LearnwithBrainly

5 0

3 years ago

Click here please. The problems are in picture format

padilas [110]

First picture:

You got the first two right (good job!), so I'll just tackle the third one. If you have to compute $f(x-4)$ , it means that you have to substitute $x-4$ in place of $x$ . Differently from the first two points, this will generate a new function, rather than a specific value:

$f(x) = \sqrt{x+4}+2 \implies f(x-4) = \sqrt{(x-4)+4}+2 = \sqrt{x}+2$

Second picture:

Given the point $(x,y)$ highlighted in the picture, you can deduce that the base is $2x$ units long (since it spans from $(-x,0)$ to $(x,0)$ ) and the height is $y$ units long (because it spans from $(x,0)$ to $(x,y)$ ). So, the area of the rectangle is the multiplication between base and height:

$A = 2xy$

But we know that $y=f(x)=\sqrt{36-x^2}$ , so we have

$A = 2x\sqrt{36-x^2}$

The domain of this function is given by the domain of the square root: we want its argument to be non, negative, so we have

$36-x^2 \geq 0 \iff x^2 \leq 36 \iff -6 \leq x \leq 6$

But since the problem is symmetric, the answer is

$0 \leq x \leq 6$

You can only see the answer $0 < x < 6$ because, if you choose $x=0$ or $x=6$ , the rectangle degenerates to a segment, and your exercise doesn't like this scenario, apparently