All categories

3 years ago

Which three values are greater than

Mathematics

1 answer:

solniwko [45]3 years ago

6 0

Answer:

3/4 is greater than 1/2

45% = 9/20 is less than 1/2

1/3 is less than 1/2

0.62 is greater than 1/2

59% = 59/100 is greater than 1/2

0.315 is less than 1/2

So, A, D and E are greater than 1/2

Hope this helps!

You might be interested in

There are 1200 students at a school and 390 of them are boys if each classroom holds 30 students how many classrooms are needed

vodomira [7]

Answer:

40 classrooms

Step-by-step explanation:

Divide 1200 by 30.

1200÷30=40

If 390 students are boys just subtract 390 from 1200.

1200-390= 810

There must be 810 girls if there are 390 boys

5 0

2 years ago

Surface area in terms of pi?

Lunna [17]

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ \cline{1-1} V=972\pi \end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies 2916\pi =4\pi r^3 \\\\\\ \cfrac{2916}{4\pi }=r^3\implies 729=r^3\implies \sqrt[3]{729}=r\implies 9=r \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a sphere}\\\\ SA=4\pi r^2\qquad \qquad \implies SA=4\pi (9)^2\implies \boxed{SA=324\pi }$

5 0

3 years ago

6cos x-6sin x=3.sqrt6

Yakvenalex [24]

Divide by 6
$cos x - sin x = \frac{\sqrt{6}}{2}$

Square both sides
$cos^2 x -2 sin x cos x + sin^2 x = \frac{3}{2}$

Simplify Left side using Trig identities: (Pythagorean, Double Angle)
$1 - sin (2x) = \frac{3}{2}$

Solve for x:
$sin (2x) = -\frac{1}{2} \\ \\ 2x = \frac{7 \pi}{6}, \frac{11 \pi}{6} \\ \\ x = \frac{7 \pi}{12}, \frac{11 \pi}{12}$

7 0

3 years ago

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$

$y-4=\frac{-3}{4}(x+2)$

Hence the equation of line is found out

6 0

2 years ago

The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel: A quadrilateral ABCD is shown with the

algol [13]

A Quadrilateral A B C D in which Sides AB and DC are congruent and parallel.

The student has written the following explanation

Side AB is parallel to side DC so the alternate interior angles, angle ABD and angle BDC, are congruent. Side AB is equal to side DC and DB is the side common to triangles ABD and BCD. Therefore, the triangles ABD and CDB are congruent by SAS.

The student has also written

angles DBC and ADB are congruent and sides AD and BC are congruent. Angle DBC and angle ADB form a pair of alternate interior angles. Therefore, AD is congruent and parallel to BC. Quadrilateral ABCD is a parallelogram because its opposite sides are equal and parallel.

Postulate SAS completely describes the student's proof.

Because if in a quadrilateral one pair of opposite sides are equal and parallel then it is a parallelogram.

6 0

2 years ago