F(x) = 3x^2+6x-2
= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5
So our function is in the form:
f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
Answer:
D
Step-by-step explanation:
an undefined slope has the same x value no matter what y value it has, therefore, D
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I would love to help, but what are the options?
Answer:
no
Step-by-step explanation:
If it is not a perfect square, then the original number cannot be a perfect square. 125 is not a perfect square [nor is 53 or 35], so 1953125 cannot be a perfect square.
