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elena-14-01-66 [18.8K]
3 years ago
12

16. Each of a group of sealed opaque envelopes contains eight bills. One envelope contains eight $1 bills, one envelope contains

eight $5 bills, and one envelope contains four $1 bills and four $5 bills. An envelope is selected at random, and a bill is taken from the envelope at random. If it is a $5 bill, what is the probability that the rest of the bills in the envelope are also $5 bills
Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

probability = 1/2

Step-by-step explanation:

Ok probability is the possibility of something happening.

So let's check the chance of $5 appearing according to how it appeared before.

4 envelopes are opened and 8 bills are inside . So total bills are 32 bills

Out of 24 bills 12 are 1$ bill

12 are $ 5 bill.

So it's a fifty fifty chance.

So the probability is 1/2

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Enter the mixed number as an improper fraction. 2 3/8 =
natali 33 [55]

Answer:

19/8

Step-by-step explanation:

To find the mixed number

Take the denominator times the whole number

8*2 = 16

Add the numerator

16+3 = 19

Put this over the denominator

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Polynomial add or subtract (-2x^2-4x+13)+(12x^2+2x-25)
BigorU [14]

1.Simplify.

-2{x}^{2}-4x+13+12{x}^{2}+2x-25−2x2−4x+13+12x2+2x−25

2.Collect like terms.

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3 years ago
6(21)+6(31) evaluate
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6 0
2 years ago
Read 2 more answers
Simplify. (-2)-3 -8 - 8 user: simplify. 6x-2
Vinvika [58]
If you would like to simplify <span>(-2)-3 -8 - 8 and 6x - 2, you can do this using the following steps:

</span><span>(-2)-3 -8 - 8 = - 2 - 3 - 8 - 8 = - 5 - 8 - 8 = - 13 - 8 = - 21

6x - 2 = 2 * (3x - 1)

The correct result would be - 21 and </span><span>2 * (3x - 1).</span>
3 0
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