Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10
0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes
q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters
so there are (10 - 6) = 4 more quarters then dimes
Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
Answer:
6^4 * 6^3
Step-by-step explanation:
M = 54 bro bro bro give me BRANLIEST
