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2 years ago

15

Giving a test to a group of students, the grades and gender are summarized below

1 answer:

Anna007 [38]2 years ago

5 0

Answer:

46/ 67

Step-by-step explanation:

The numbers of students irrespective of grades is;

The sum of the last roll of numbers:

10+24+ 33+ 67 = 134

The number of males irrespective of grades is the sum of the numbers in the male row ;

7 +20+ 14 +41= 82

The numbers of students with grade A is the first column at the last row and is 10;

Hence;

the probability that the student was male OR got an 'A' is

the probability that the student was male plus the probability that he/she got an 'A'.

The probability that it's a male is ;

Number of males/ total number of students

=82/134

The probability that he got an A is;

The number of students that got A/ the total number of students;

10/134

Hence

the probability that the student was male OR got an 'A' is;

82/ 134 + 10/134 = 92/134 = 46/ 67

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Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large r

Anettt [7]

Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

$\bar x = \frac{\sum x}{n}$ ---- mean

Where:

$n = 4$ ---- number of rows

$R = Highest - Lowest$ --- range

So, we have:

Sample 1

$\bar x_1 = \frac{1027+ 994 +977 +994 }{4}$

$\bar x_1 = 998$

$R_1 = 1027- 994$

$R_1 = 33$

Sample 2

$\bar x_2 = \frac{975 +1013 +999 +1017}{4}$

$\bar x_2 = 1001$

$R_2 = 1017 - 975$

$R_2 = 42$

Sample 3

$\bar x_3 = \frac{988 +1016 +974 +997}{4}$

$\bar x_3 = 993.75$

$R_3 = 1016-974$

$R_3 = 42$

Sample 4

$\bar x_4 = \frac{998 +1024 +1006 +1010}{4}$

$\bar x_4 = 1009.5$

$R_4 = 1024 -998$

$R_4 = 26$

Sample 5

$\bar x_5 = \frac{990 +1012 +990 +1000}{4}$

$\bar x_5 = 998$

$R_5 = 1012 -990$

$R_5 = 22$

Sample 6

$\bar x_6= \frac{1016 + 998 +1001 +1030}{4}$

$\bar x_6= 1011.25$

$R_6= 1030-998$

$R_6= 32$

Sample 7

$\bar x_7 = \frac{1000 +983 +979 +971}{4}$

$\bar x_7 = 983.25$

$R_7 = 1000-971$

$R_7 = 29$

Sample 8

$\bar x_8 = \frac{973 +982 +975 +1030}{4}$

$\bar x_8 = 990$

$R_8 = 1030-973$

$R_8 = 57$

Sample 9

$\bar x_9 = \frac{992 +1028 +991 +998}{4}$

$\bar x_9 = 1002.25$

$R_9 = 1028 -991$

$R_9 = 37$

Sample 10

$\bar x_{10} = \frac{997 +1026 +972 +1021}{4}$

$\bar x_{10} = 1004$

$R_{10} = 1026 -972$

$R_{10} = 54$

Sample 11

$\bar x_{11} = \frac{990 +1021 +1028 +992}{4}$

$\bar x_{11} = 1007.75$

$R_{11} = 1028 -990$

$R_{11} = 38$

Sample 12

$\bar x_{12} = \frac{1021 +998 +996 +970}{4}$

$\bar x_{12} = 996.25$

$R_{12} = 1021 -970$

$R_{12} = 51$

Sample 13

$\bar x_{13} = \frac{1027 +993 +996 +996}{4}$

$\bar x_{13} = 1003$

$R_{13} =1027 -993$

$R_{13} =34$

Sample 14

$\bar x_{14} = \frac{1022 +981 +1014 +983}{4}$

$\bar x_{14} = 1000$

$R_{14} = 1022 -981$

$R_{14} = 41$

Sample 15

$\bar x_{15} = \frac{977 +993 +986 +983}{4}$

$\bar x_{15} = 984.75$

$R_{15} = 993-977$

$R_{15} = 16$

8 0

2 years ago

The exterior angles of an octagon are 42°, 55°, 39°, 20°, 62°, 45°, and 47°. What is the measure of the eighth exterior angle? S

marysya [2.9K]

The sum of exterior angles of a polygon = 360<span>°

Thus, the eighth exterior angle is equal to
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6 0

3 years ago

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Find the perimeter of a ruler that measures 6 inches by 5/6

alukav5142 [94]

Answer:

41/3

Step-by-step explanation:

6 + 6 + 5/6 + 5/6

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2 years ago

Michelle's mother bought 7 large pizzas for her birthday party. Each large pizza is cut into eighths. if 5/8 of the total slices

nirvana33 [79]

So we know that there are 8 slices per large pizza (7), so a total of 56 slices
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56-35 is 21
so there are 21 slices left over

5 0

2 years ago

In triangle abc, the length of side and is 10 inches and the length of side be is 17 inches . Which of the following could be th

earnstyle [38]

Answer:

a^2=b^2+c^2.

a^2=10^2+17^2.

a^2=100+289.

a^2=389.

a=√389.

a=19.72~20cm.

5 0

2 years ago