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andrew-mc [135]
3 years ago
12

How do you predict products?

Chemistry
1 answer:
mamaluj [8]3 years ago
4 0
Is this a <span>Multiple-choice exercise</span>
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Why might a geologist ask an analytical chemist to help identify the minerals in a rock.
Galina-37 [17]

 A geologist will ask an analytical chemist to help identify the minerals in a rock because an analytical chemist studies the composition of matter and, therefore, can identify the minerals.

The analytical chemist does this by determining the crystal structure as a matter of routine using X-ray and electron diffraction techniques.

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8 0
2 years ago
How many mono-; di- ; and trichloro derivatives are possible for cyclopentane?
Studentka2010 [4]
Mono - 1 Di- 2 Tri - 4
8 0
3 years ago
A scientist is trying to determine whether a certain substance is radioactive. Which question would be most helpful to ask?
oksian1 [2.3K]
Well a question to ask would be if the mass of the material has changed significantly as that would determine that the substance is radioactive or if there have been any high readings found by a Geiger meter in certain period of time

hope that helps 
3 0
3 years ago
What is the atomic mass of an atom that has 3 protons and 4 neutrons
Ainat [17]
Atomic Mass is equal to the sum of the number of protons and neutrons.

Thus the atomic mass = 3  +  4
  
                                    =   7

5 0
3 years ago
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
3 years ago
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