In art class, the students were asked to draw a circle inside the square shown in the figure such that each of the sides of the

Can you please answer my homework, its about sets.

Katyanochek1 [597]

The value of the set (A∪C)'∩B is {9 , 12} .

A subfield of mathematical logic called set theory examines sets, which are essentially collections of objects.

Set theory is a discipline of mathematics that largely addresses problems that are pertinent to mathematics as a whole, despite the fact that any kind of object can be constructed into a set.
Set theory is founded on a simple binary relationship between an object o and a set A.
It is written as o A if o is a part (or member) of A. Members of a set are enumerated with commas to denote separation when describing them, or a property of those parts is enclosed in braces.
Sets can be associated by the membership relation since they are objects.

The given sets are:

U ={1,2,3,4,5,6,7,8,9,10,11,12,13}

A = {3,7,11,13}

B = {3,6,9,12,13}

C = {2,3,5,6,7,8}

Now B' = {1,2,4,5,7,8,10,11}

b) B'∩C = {2,5,7,8,}

c) A∪C = {2,3,5,6,7,8,11,13}

(A∪C)' = {1,4,9,10,12}

(A∪C)'∩B = {9 , 12}

Hence the value of the set (A∪C)'∩B is {9 , 12} .

To learn more about set visit:

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6 0

2 years ago

Give the reflection of the point across the given axis 2,-5,y-axis

nydimaria [60]

Answer:

-2,5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Element X decays radioactively with a half life of 12 minutes. If there are 160

Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

$X(t) = X(0)(1-r)^{t}$

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

So

$X(t) = X(0)(1-r)^{t}$

$X(t) = 160(1-r)^{t}$

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

$X(t) = 160(1-r)^{t}$

$80 = 160(1-r)^{12}$

$(1 - r)^{12} = 0.5$

$\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}$

$1 - r = 0.9438$

So

$X(t) = 160(1-r)^{t}$

$X(t) = 160(0.9438)^{t}$

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

$X(t) = 160(0.9438)^{t}$

$2 = 160(0.9438)^{t}$

$(0.9438)^{t} = \frac{2}{160}$

$\log{(0.9438)^{t}} = \log{\frac{2}{160}}$

$t\log{0.9438} = \log{\frac{2}{160}}$

$t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}$

$t = 75.8$

It would take 75.8 minutes for the element to decay to 2 grams.

6 0

3 years ago

How much is three quarters of an hour

Pani-rosa [81]

Answer=45minutes

three quarters= 3/4 or 75%

an hour is 60 minutes

3/4*60minutes=45minutes

5 0

4 years ago

Read 2 more answers

Cant remember how to do this :( Please help !!

Juli2301 [7.4K]

Answer:

B

Step-by-step explanation:

1) Look at the y-intercepts.

The y-intercepts on both equations are the same: 5. That means both equations touch the y-axis at (0,5).

That means we can rule out both A & C.

2) Calculate the rate of change (a.k.a. slope) of f(x).

To do this, we must use two points to find the change of y over the change of x. From the graph, we can use the points (1,2) and (2,-1).

Δy / Δx = $\frac{-1 - (2)}{2-1} = \frac{-3}{1} = -3$

<em>*The little triangles are the Greek symbol delta. They mean change in...*</em>

That means that the slope of f(x) is -3.

3) Figure out the rate of change (a.k.a. slope) of g(x).

To do this, all we have to do is look at the equation. It is written in y = mx + b format where m = slope and b = y-intercept. That means the slope is 5 as in place of "m" there is a 5.

4) The Answer

The answer is B because 5 [the rate of change for g(x)] is greater than -3 [the rate of change for f(x)].

4 0

4 years ago