11.It is reffered to as the blanket around the atmosphere because it raps in all the air
12.water can never dissapear as long as we keep digesting and drinking water
For ever 1 mole of nitrogen you need 3 moles of hydrogen to make 2 moles of Ammonia.
We only have 10 moles of hydrogen so that is the limiting as there is more nitrogen then hydrogen in this particular case.
Therfore the ratio is 2 ammonia to 3 hydrogen [2:3]
Do 2/3which is 0.6667. This is how many moles of ammonia you get per mole of hydrogen.
Multiply that by 10 and you get 6.67 moles of Ammonia produced [3 significant figures]
Answer- troposphere
The troposphere is the only atmospheric layer that can support life.
Answer: The freezing point (in °C) of a 0.743 m aqueous solution of KCI is .
Explanation:
Given: Molality = 0.743 m
for water =
The equation for dissociation of KCl when dissolved in water is as follows.
As it is giving 2 ions. Therefore, Van't Hoff factor for it is equal to 2.
Formula used to calculate the freezing point is as follows.
where,
i = Van't Hoff factor
= molal depression constant
m = molality
Substitute the values into above formula as follows.
Thus, we can conclude that the freezing point (in °C) of a 0.743 m aqueous solution of KCI is .
Answer:
68%
Explanation:
Since we need a percentage we can use any number we want for our initial value.
5(1/2)^900/1620 = 3.40
(3.40 / 5)*100 = 68%
To make sure lets use a different initial amount
1(1/2)^900/1620 = 0.68
(0.68/1) * 100 = 68%