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gladu [14]
3 years ago
11

Write the symbol for every chemical element that has atomic number greater than 55 and atomic mass less than 144.0 u

Chemistry
1 answer:
laila [671]3 years ago
3 0
You will need a periodic table to help you answer this problem. The atomic numbers are arrange from lowest to highest in the periodic table. You can locate element number 55 to be Cesium with an atomic weight of 132.905 amu. So, you start from element 56. The following elements are:

56     Barium       137.328 amu
57     Lanthanium   138.905 amu
58     Cerium       140.116 amu
59     <span>Praseodymium    140.908 amu
60     Neodymium   144.243 amu

Neodymium is already greater than 144 amu. Therefore, these elements only include Barium, Lanthanium, Cerium and Praseodymium.</span>
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Dmitriy789 [7]

Answer:

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8 0
2 years ago
Given a balanced chemical equation below: 3Cu(s) + 2H3PO4 --- &gt; Cu3(PO4)2 + 3H2 How many moles of copper are needed to react
Harman [31]

Answer:

7.5 moles

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

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4 0
3 years ago
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mihalych1998 [28]
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So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.

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The effect on density would be that it would erroneously appear to be greater

Hope this helps!

Good luck
6 0
3 years ago
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