Answer:
4.15 M
Explanation:
In order to find the molarity of a stock solution of Z, we use the formula;
Co = 10pd/M
where;
p = percentage by mass of Z
d = density of Z
M= molar mass of Z
Substituting values;
Co= 10 * 35 * 1.4/118
C0= 4.15 M
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial pressure (P1) = 1atm
Initial temperature (T1) = 0°C = 0°C + 273 = 273K
Final temperature (T2) = 280°C = 280°C + 273 = 553K
Final pressure (P2) =...?
Step 2:
Determination of the new pressure of the gas.
Since the volume of the gas is constant, the following equation:
P1/T1 = P2/T2
will be used to obtain the pressure. This is illustrated below:
P1/T1 = P2/T2
1/273 = P2 / 553
Cross multiply
273x P2 = 553
Divide both side by 273
P2 = 553/273
P2 = 2.03atm
Therefore, the new pressure of the gas will be 2.03atm
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
Answer:It is always greater than the actual mechanical advantage because all machines must overcome friction. The mechanical advantage of a machine may be greater than, less than, or equal to 1, depending on the type of machine.
