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Olegator [25]
2 years ago
14

List any five items that can be found in a Science portfolio​

Chemistry
1 answer:
ad-work [718]2 years ago
6 0

Answer:

physical projects

Journal entries

Materials

Lab reports

Artworks

Explanation:

Definition of a Portfolio:

Portfolio can be defined as a physical collection of student work that includes materials such as written assignments, completed tests, artwork, lab reports, physical projects and other material evidence of learning progress and academic accomplishment, including awards and honors,

A portfolio is a long-term form of self reflection and assessment that students do together.

Portfolios are a great way to demonstrate the competencies you would list on a resume or talk about in a science interview

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D all of the above answers are correct
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Select the correct answer. Which of these elements is a transition metal?
PtichkaEL [24]

I don't see the options for an answer, so here is a list of all of the transition metals lol

  • <em>Scandium</em>
  • <em>Titanium</em>
  • <em>Vanadium</em>
  • <em>Chromium</em>
  • <em>Manganese</em>
  • <em>Iron</em>
  • <em>Cobalt</em>
  • <em>Nickel</em>
  • <em>Copper</em>
  • <em>Zinc</em>
  • <em>Yttrium</em>
  • <em>Zirconium</em>
  • <em>Niobium</em>
  • <em>Molybdenum</em>
  • <em>Technetium</em>
  • <em>Ruthenium</em>
  • <em>Rhodium</em>
  • <em>Palladium</em>
  • <em>Silver</em>
  • <em>Cadmium</em>
  • <em>Lanthanum</em>
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8 0
2 years ago
A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

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3 years ago
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Explanation:

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