All categories

3 years ago

Which of the following processes occurs in the cells of plants?

Physics

1 answer:

Gnom [1K]3 years ago

7 0

Answer:

A., B. & C.

Explanation:

All apply, because all these happen in a plant.

You might be interested in

An explosion in a rigid pipe shoots three balls out of its ends. A 6 gam ball comes out the right end. A 4 gram ball comes out t

wariber [46]

Answer:

The third ball emerges from the right side.

Explanation:

This is a conservation of Momentum problem

In an explosion or collision, the momentum is always conserved.

Momentum before explosion = Momentum after explosion

Since the rigid pipe was initially at rest,

Momentum before explosion = 0 kgm/s

- Taking the right end as the positive direction for the velocity of the balls

- And calling the speed of the 6 g ball after explosion v

- This means the velocity of the 4 g ball has to be -2v

- Mass of the third ball = m

- Let the velocuty of the third ball be V

Momentum after collision = (6)(v) + (4)(-2v) + (m)(V)

Momentum before explosion = Momentum after explosion

0 = (6)(v) + (4)(-2v) + (m)(V)

6v - 8v + mV = 0

mV - 2v = 0

mV = 2v

V = (2/m) v

Note that since we have established that the sign on m and v at both positive, the sign of the velocity of the third ball is also positive.

Hence, the velocity of the third ball according to our convention is to the right.

Hope this Helps!!!

5 0

4 years ago

Read 2 more answers

When the velocity of the car is constant the force of friction is?

miv72 [106K]

..... equal to the force from the engine pushing the car forward.

That's why the car is not accelerating. The horizontal forces on it
are balanced.

6 0

3 years ago

Calculate the force of gravity on the 0.60-kg mass if it were 1.3×107m above Earth's surface (that is, if it were three Earth ra

Vladimir79 [104]

The force of gravity between two objects is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the mass of the object is $m_1=0.60 kg$ , while the Earth's mass is $m_2=5.97 \cdot 10^{24} kg$ . Their separation is $r=1.3 \cdot 10^7 m$ , therefore the gravitational force exerted on the object is
$F=(6.67 \cdot 10^{-11}m^3 kg^{-1} s^{-2}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=1.4 N$

5 0

3 years ago

The resulting net force of an object is represented below. →10 N Which most likely represent the forces acting on the object?

kobusy [5.1K]

a friction force 10 N less than the applied force, a normal force equal to the gravtiational force

4 0

3 years ago

Read 2 more answers

A 1kg skateboard sits at the top of a ramp 20 fr off the ground . How much potential energy does it have ?

Finger [1]

Answer:

196J

Explanation:

Given parameters:

Mass of skateboard = 1kg

Height off the ground = 20m

Unknown:

Potential energy = ?

Solution:

The potential energy is the energy due to the position of a body above the ground.

It is mathematically expressed as:

Potential energy = mass x acceleration due gravity x height

Potential energy = 1 x 9.8 x 20 = 196J

8 0

3 years ago