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3 years ago

The linear momentum of a runner in a 100m dash is 750kg m/s. If the runners speed is 10m/s, What is his mass

Physics

1 answer:

Brilliant_brown [7]3 years ago

7 0

Answer:

The mass of the runner is 75 kg

Explanation:

Recall that the linear momentum is defined as the product of the mass of the object in motion times its velocity: P = m * v

Therefore, for our case we have;

750 kg m/s = m * 10 m/s

solving for the mass (m) we get:

m = 750/10 kg =75 kg

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The density of a certain planet varies with radial distance as: rho(r)= rho0(1-αr/R0) where R0= 25.12 x 10^6 m is the radius of

Free_Kalibri [48]

Answer:

The total mass of this planet is $2.0689\times10^{26}\ kg$

Explanation:

Given that,

Radius $R_{0}=25.12\times10^{6}\ m$

Density $\rho_{0}=3800.0\ kg/m^3$

Central density $\alpha=0.24$

The density of a certain planet varies with radial distance as

$\rho(r)=\rho_{0}(1-\dfrac{\alpha r}{R_{0}})$

We need to calculate the total mass of this planet

Using formula of density

$\rho=\dfrac{M}{V}$

$M=\rho\times V$

On integrating

$M=\int_{0}^{R_{0}}{\rho(r)\times4\pi r^2 dr}$

Put the value of $\rho{r}$ into the formula

$M=\int_{0}^{R_{0}}{\rho_{0}(1-\dfrac{\alpha r}{R_{0}})\times4\pi r^2 dr}$

$M=\rho_{0}\times 4\pi\int_{0}^{R_{0}}{(r^2-\dfrac{\alpha r^3}{R_{0}})dr}$

$M=\rho_{0}\times 4\pi\times(\dfrac{r^3}{3}-\dfrac{\alpha\times r^4}{4\times R_{0}})_{0}^{R_{0}}$

$M=4\pi\times\rho_{0}\times R_{0}^3(\dfrac{4-3\alpha}{12})$

Put the value into the formula

$M=4\pi\times3800.0\times(25.12\times10^{6})^3(\dfrac{4-3\times0.24}{12})$

$M=2.0689\times10^{26}\ kg$

Hence, The total mass of this planet is $2.0689\times10^{26}\ kg$

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Traveling wave is a wave that is not confined to the space along medium.

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4 years ago

Which describes what happens when a balloon is rubbed with a wool cloth?

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AleksAgata [21]

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