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Burka [1]
3 years ago
14

A grating whose slits are 3.2x10^-4 cm apart produces a third-order fringe at a 25.°0 angle. What is the wavelength of light tha

t is used?
Physics
1 answer:
Ber [7]3 years ago
7 0

Answer:

The light used has a wavelenght of 4.51×10^-7 m.

Explanation:

let:

n be the order fringe

Ф be the angle that the light makes

d is the slit spacing of the grating

λ be the wavelength of the light

then, by Bragg's law:

n×λ = d×sin(Ф)

λ = d×sin(Ф)/n

λ = (3.2×10^-4 cm)×sin(25.0°)/3

  = 4.51×10^-5 cm

  ≈ 4.51×10^-7 m

Therefore, the light used has a wavelenght of 4.51×10^-7 m.

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True or False: Radio waves are the longest and have the least energy of any wave.​
Alona [7]

Answer:

t

Explanation:

8 0
3 years ago
Read 2 more answers
How big/small can radio waves be?
Volgvan

Answer:

Radio waves have the longest wavelengths in the EM spectrum, according to NASA, ranging from about 0.04 inches (1 millimeter) to more than 62 miles (100 kilometers).

                        Band              Frequency range Wavelength range

Very Low Frequency (VLF) 3 to 30 kHz 10 to 100 km

Low Frequency (LF) 30 to 300 kHz 1 m to 10 km

Explanation:

4 0
4 years ago
Suppose you wanted to use the Earth's magnetic field to make an AC generator at a location where the magnitude of the field is 0
Likurg_2 [28]

Answer:

The angular velocity I would have to rotate it in order to generate an emf of amplitude 1.0 V is 254.65 rad/s

Explanation:

given information:

B = 0.5 mT = 0.0005 T

N = 1000

r = 5 cm = 0.05 m

emf, ε = 1 V

according to Faraday's law

ε = -N dΦ/dt, Φ = B A

  = - N d( B A)/dt

  = - N d( B A cos ωt)/dt

   = - N B A d(cos ωt)/dt

   = N B A ω sin ωt

A = πr², so

ε = N B πr² ω sin ωt

where

ε = emf

N = number of coil turn

B = magnetic field

r = radius

ω = angular velocity

Φ = magnetic flux

emf maximum, sin ωt = 1. So,

ε = N B πr² ω

ω = ε/N B πr²

   = 1/[(1000) (0.0005) π (0.05)²

   = 254.65 rad/s

6 0
4 years ago
3. How much work is done when you pull a 6 N wagon for 5 meters?
8090 [49]

Answer:

<h2>30 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 6 N

distance = 5 m

We have

workdone = 6 × 5 = 30

We have the final answer as

<h3>30 J</h3>

Hope this helps you

3 0
3 years ago
A child in a boat throws a 5.80-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 24.6kg and the ma
Sergio [31]

Answer:

-0.912 m/s

Explanation:

When the package is thrown out, momentum is conserved. The total momentum after is the same as the total momentum before, which is 0, since the boat was initially at rest.

(m_c + m_b)v_b + m_pv_p = 0

where m_c = 24.6 kg, m_b = 39 kg, m_p = 5.8 kg are the mass of the child, the boat and the package, respectively. , v_p = 10m/s, v_b are the velocity of the package and the boat after throwing.

(24.6 + 39)v_b + 5.8*10 = 0

63.6v_b + 58 = 0

v_b = -58/63.6 = -0.912 m/s

3 0
4 years ago
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