To solve this problem we will apply the concept of centripetal acceleration. This type of acceleration is described as the product between the square of the angular velocity and the turning radius. Mathematically the expression can be expressed as

Here,
Angular velocity
r = Radius
Our values are given as,


Replacing,


Therefore the electron's centripetal acceleration is 
Answer:
The total work done by Brad each day is 176400 J
Explanation:
Hi there! The work done by a force (F) pointed in the same direction as the displacement (d) is calculated as follows:
W = F · d
The force applied is equal to the weight of Brad, that is calculated as follows:
Weight = m · g
Where:
m = mass of Brad
g = acceleration due to gravity (9.8 m/s²)
Then:
Weight = 60 kg · 9.8 m/s² = 588 N
Let´s find the vertical distance traveled by Brad each day:
He exercises 20 min per day. Each minute Brad does 60 steps. In total, Brad steps up (20 min · 60 steps/min) 1200 steps. If each step has a height of 0.25 m, the total distance traveled by Brad will be
(1200 steps · 0.25 m/step) 300 m.
Then, the total work done by Brad is
W = F · d
W = 588 N · 300 m
W = 176400 J
The total work done by Brad each day is 176400 J
C im pretty sure?.........
For maximum radiation protection the suggested distance between array fan-beam scanner source and the operator is 2m.
The Fan beam 5 position reference system (PRS) uses accurate time-of-flight laser technology to determine vessel position relative to custom reflectors.
A fan beam allows only the measurement of the azimuth angle. A fan beam, one with a narrow beam width in azimuth and a broad beam width in elevation, can be obtained by illuminating an asymmetrical section of the paraboloid.
The operators’ desk should be positioned at least 1m away from a pencil beam, and at least 2m from a fan-beam system. Some older models, that are not now common, require a distance of 3.5 m.
To learn more about scanner here
brainly.com/question/28174696
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Answer:

Explanation:
It is given that,
Area of cross section of the pipe, 
Area of cross section of the another pipe, 
Speed of water in first pipe, 
To find,
Speed of the water flowing in the second pipe.
Solve,
Let
is the speed of water flowing in the second pipe. The relation between the area of cross section and the velocity is given by the continuity equation. It is given by :




Therefore, the water is flowing in the second pipe at the rate of 8 m/s.