Smaller circle:
diameter = 9 ft
radius = diameter/2 = (9 ft)/2 = 4.5 ft
A = pi(r^2) = 3.14159 * (4.5 ft)^2 = 63.62 ft^2
Larger circle:
diameter = 20 ft
radius = diameter/2 = (20 ft)/2 = 10 ft
A = pi(r^2) = 3.14159 * (10 ft)^2 = 314.159 ft^2
Difference = larger are - smaller area
Difference = 314.16 ft^2 - 63.62 ft^2 = 250.54 ft^2
Answer: About 251 ft^2
31-40. C. 12 students sold that many, therefore it's the most.
Nice, already in vertex form
y=a(x-h)^2+k
(h,k) is vertex
therfor since (-3,6) is vertex
we are looking for something like
y=a(x-(-3))^2+6 simplified to
y=a(x+3)^2+6
A is ansre
First, let's list the lengths of the sides in descending order.
Lengths of sides of quadrilateral ABCD: 20, 18, 14, a
Lengths of sides of quadrilateral EFGH: b, c, 6, 5
From the listings above, we see that he sides measuring 14 and 6 are corresponding.
We are looking for c which corresponds to 18.
14 is to 6 is as 18 is to c
14/6 = 18/c
7/3 = 18/c
7c = 3 * 18
7c = 54
c = 54/7 = 7 5/7
Answer: 7 5/7 feet
Answer:
(-4, 5)
Step-by-step explanation (work shown in attached picture):
1) Since x is already isolated in the first equation, substitute that value for x into the other equation to find y. So, substitute 16-4y for the x in 3x + 4y = 8, then solve for y. This gives us y = 5.
2) Now, substitute that given value for y back into any one of the equations to find x. I chose to do it in the first equation. Substitute 5 for the y in x = 16-4y, then solve for x this time. This gives us x = -4.
Since x = -4 and y = 5, the solution is (-4, 5).
