The ship movement is an illustration of distance and bearing
The ship is 31.97 miles from its point of departure
<h3>The distance from the point of departure?</h3>
The given parameters are:
- Distance east = 40 milies
- Distance southwards = 70 miles
- Angle = 12 degrees
See attachment for the image of the above parameters
The distance (x) from the point of departure is then calculated using the following cosine function
a^2 = b^2 + c^2 - 2bc * cos(Ф)
So, we have:
x^2 = 40^2 + 70^2 - 2 * 40 * 70 * cos(12)
Evaluate the exponent and the product
x^2 = 6500 - 5477.63
Evaluate the difference
x^2 = 1022.37
Evaluate the exponent
x = 31.97
Hence, the ship is 31.97 miles from its point of departure
Read more about distance and bearing at:
brainly.com/question/24142612
Y=(11/8)x+6
subtract the 8y to the right then add the 48 to the left then divide by 8
HERONS TROUT MINNOWS AQUATIC INSECTS ALGAE
I multiplied the dimensions and divided it by 75, got 8.75 but you need to round in this situation, so 9
hope this helps :)
Answer:
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