<h3>
Answer: B) Only the first equation is an identity</h3>
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I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
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Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
Answer:
length is 26 and width is 23
Step-by-step explanation:
let width be x
then length is 3+x since it is 3 more than the width
perimeter of a rectangle = 2l + 2w
98=2 [3+x] + 2x
98=6+2x+2x
98=6+4x
98-6=4x
92=4x
x=23
width is 23 and
breadth is 26
Answer: 2(-5+3) is the equivalent of -10+6. the value is -4
Step-by-step explanation:
The values of x and y are 8 and 0 respectively.
<em><u>Explanation</u></em>
As 'p' is located at (0,0) and 'r' is located at (-12,0) , that means both 'p' and 'r' are on the x-axis. So point 'q' will be also on the x-axis , and 'q' is located at (x,y)
So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)
Now, using the Distance formula, length of 'pq' 
and length of 'pr' 
Given that, pq : pr =2/3
So....
Thus, the values of x and y are 8 and 0 respectively.
