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3 years ago

The sixth grade debate team has a boy to girl ratio of 3:8. Which of the following ratios is equivalent to this ratio?

Mathematics

1 answer:

hram777 [196]3 years ago

6 0

Answer:

wow this your first Q

Step-by-step explanation:

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You throw a softball into the air with an initial upward velocity of 38 ft/s and an initial height of 5 feet. Use the vertical m

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2 years ago

Solve for t: t ÷ 5 = 8

DIA [1.3K]

Answer:

Step-by-step explanation:

Equation is t÷5=8

first you multiply 5 on each to cancel it out

t÷5*5=8*5

solve to get

t=40

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3 years ago

What is the equation of the parabola, in vertex form, with focus at (2,-4) and directrix y=-6?

viktelen [127]

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3 years ago

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serious [3.7K]

Answer: y-int ( 0, 0.4 ) x-int ( 0.3, 0 )

Step-by-step explanation:

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2 years ago

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The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

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3 years ago