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Arte-miy333 [17]
3 years ago
5

The sixth grade debate team has a boy to girl ratio of 3:8. Which of the following ratios is equivalent to this ratio?

Mathematics
1 answer:
hram777 [196]3 years ago
6 0

Answer:

wow this your first Q

Step-by-step explanation:

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Yooooooooooooooooooooooooo
stira [4]

Answer:

3/2

Step-by-step explanation:

Rise over run meaning how many up over how many over (would be a negative rise if the line was \ instead of /)

find where the line intersects with the corner of the graph lines and plot from there.

Mark me as brainliest if this helps!

8 0
2 years ago
Read 2 more answers
8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.
loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

^8C_4\times ^9C_5\times^9C_2\times^7C_3

=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0
3 years ago
9(x/3+1)>6 can you help me with this.
dybincka [34]

Answer:

the answer is 3 raised ro the third power

7 0
3 years ago
Read 2 more answers
Can you help me find the composition of funtions​
balandron [24]

where's the question? x

6 0
3 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
3 years ago
Read 2 more answers
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