The sixth grade debate team has a boy to girl ratio of 3:8. Which of the following ratios is equivalent to this ratio?

What is the gradient of the graph shown?<br> Give your answer in its simplest form.

Amiraneli [1.4K]

Answer:

-2

Step-by-step explanation:

I think this was the question you were talking about.

4 0

3 years ago

The spinner below is spun, then a month of the year is randomly selected. Find the probability of P(unshaded, then a month that

lana [24]

Answer:

C)150

Step-by-step explanation:

P (blue) fraction = 2/8 decimal=.25 percent=25%

P(purple) fraction=0/8 decimal=0 percent =0%

P(not green) fraction=5/8 decimal=.625 percent= 62.5%

P(not brown) fraction=8/8 decimal=1 percent =100%

2)Refer to the table on air travel selected airports. Suppose a flight that arrived at El Centro is selected at random. What is the probability that the flight did not arrive on time? write your answer as a fraction, decimal and percent.

80% on time so 20% are not on time

20/100 ÷ 20 =1/5

20%, .2, 1/5

3)The spinner has 8 sectors labeled with letters. Each sector of the spinner below is the same size, as shown.

If the arrow is spun 400 times , how many times would it be expected to land on a sector labeled B?

A)50 C)150

B)100 D)250

PLEASE MARK ME AS BRAINLIEST

7 0

3 years ago

I need the answer how to do

IrinaVladis [17]

Make a bar graph about the length of letters in an animal's name

5 0

3 years ago

A grocery store sells a bag of 4 oranges for $2.84. If Arianna spent $3.55 on oranges,

zhannawk [14.2K]

$4/3=$1.33 per pound.
$9/8 = $1.13 per pound.
The second one is cheaper.

3 0

3 years ago

Read 2 more answers

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago