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andreev551 [17]
2 years ago
6

What are the solutions of the following system? startlayout enlarged left-brace 1st row x squared y squared = 25 2nd row 2x y =

25 endlayout (0, –5) and (–5, 5) (0, –5) and (5, –15) (0, –5) and (–4, 3) (0, –5) and (4, –13)
Mathematics
1 answer:
salantis [7]2 years ago
6 0

The quadratic equation has no real roots. This means the line and point has no point of intersection.

<h3>System of equations</h3>

System of equations are equations that is more than one and have two or more unknowns.

Given the simultaneous equation

x^2 + y^2 = 25

2x + y = 25

from equation 2;

y = 25 - 2x ................3

Substitute equation 3 into 1 to have:

x^2 + (25-2x)^2 = 25

x^2 + 625 - 100x + 4x^2 = 25

5x^2 -100x + 600 = 0

x^2 -20x + 120= 0

Hence the quadratic equation has no real roots. This means the line and point has no point of intersection,

Learn more on system of equation here: brainly.com/question/25976025

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To write the equation in its slope-intercept form, y = mx + b, we need to find the slope (m) of the line and its y-intercept (b).

Given the points (0, 9) and (9, 19), we can solve for the slope of the line using the following formula:

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