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andreev551 [17]
2 years ago
6

What are the solutions of the following system? startlayout enlarged left-brace 1st row x squared y squared = 25 2nd row 2x y =

25 endlayout (0, –5) and (–5, 5) (0, –5) and (5, –15) (0, –5) and (–4, 3) (0, –5) and (4, –13)
Mathematics
1 answer:
salantis [7]2 years ago
6 0

The quadratic equation has no real roots. This means the line and point has no point of intersection.

<h3>System of equations</h3>

System of equations are equations that is more than one and have two or more unknowns.

Given the simultaneous equation

x^2 + y^2 = 25

2x + y = 25

from equation 2;

y = 25 - 2x ................3

Substitute equation 3 into 1 to have:

x^2 + (25-2x)^2 = 25

x^2 + 625 - 100x + 4x^2 = 25

5x^2 -100x + 600 = 0

x^2 -20x + 120= 0

Hence the quadratic equation has no real roots. This means the line and point has no point of intersection,

Learn more on system of equation here: brainly.com/question/25976025

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Step-by-step explanation:

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4 0
2 years ago
The following blank indicates a missing operation in the equation.
Natalija [7]
The answer would be 5/2q+9r+6r-20s

Explanation
We have the equation
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which would equal
5/2q+15r-20s

so with the information
We can subtract 6r from 15r to get 9r
15r-6r=9r
+9r would be the missing piece

So we substitute it in to make the equation true.
5/2q(+9r)+6r-20s
Hope this helps or was correct
3 0
3 years ago
12 The diagram shows 3 identical circles,
Goshia [24]

Answer:

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7 0
3 years ago
Y = 7x (6/7,-1/4) ….
oksano4ka [1.4K]

Answer:

This point is not on the line, NOT TRUE

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

           b represents the y-intercept

where the format of a point is (x, y)

<u>Given:</u> y = 7x (6/7, -1/4)

we can plug in the point (6/7, -1/4)

-1/4 = 7(6/7)

-1/4 = 6

<em>-1/4 does not equal 6 so this point is not on the line</em>

Learn more about slope and y-intercept here: brainly.com/question/12763756

7 0
2 years ago
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