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KIM [24]
3 years ago
11

The measure of an exterior angle at n measures 99�. m�l � __1 3 x� and m�m � __2 3 x�. find m�l, m�m, and m�lnm.

Mathematics
1 answer:
kirill [66]3 years ago
8 0
You should ask your parent/guardian
 or teacher if needed! Merry Christmas!
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A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
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Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

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perimeter=18\frac{1}{2}\\\\length=5

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Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

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3 years ago
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in a typical bag of skittles, the ratio of red to yellow skittles is 3 to 7. If there are 40 skittles altogether, how many red s
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