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kogti [31]
3 years ago
12

Can u answer this? Mass: 126 g Volume: 15 cm to the third power Density:?

Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

Calculate density

Weight/mass

126

g

Volume

15

cm³

Density

8,400

kg/m³

Explanation:

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Answer:

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Explanation:

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What is the name of the polyatomic ion with the molecular formula<br> SO32-
IceJOKER [234]

Answer:

sulfite ion SO32

Explanation:

A molecular ion is a covalently bonded set of two or more atoms, or of a metal complex, that can be considered to behave as a single unit and that has a net charge that is not zero.

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3 years ago
acid-catalyzed hydration of 1-methylcyclohexene gives two alcohols. The major product does not undergo oxidation, while the mino
noname [10]

Answer:

Major product does not undergo oxidation since it is a tertiary alcohol whereas minor product undergoes oxidation to ketone as it is  secondary alcohol.

Explanation:

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In this case, given the attached picture, the hydration of the 1 methylcyclohexene yields to alcohols; 1-methylcyclohexan-1-ol and 1-methylcyclohexan-2-ol. Thus, since the OH in the 1-methylcyclohexan-1-ol (major product) is bonded to a tertiary carbon (bonded with other three carbon atoms) it is not able to increase the number of oxygen bonds (oxidation) as it already attained the octet whereas the 1-methylcyclohexan-2-ol (minor product) is able to undergo oxidation to ketone as the carbon bonded to it is secondary (bonded with other two carbon atoms), so one extra bond the oxygen is allowed to be formed to carbonyl.

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7 0
3 years ago
What is measured in the radiocarbon dating of organic materials
natita [175]

Answer:

The decay of carbon-14 (14C)

Explanation:

The decay of carbon-14 is used to estimate the age of raw materials, such as paper and parchment

(loc.gov)

3 0
3 years ago
method to measure soluble organic carbon in seawater includes oxidation of the organic materials to CO2 with K2S2O8, followed by
dusya [7]

Answer:

The ppm carbon in the seawater is 104.01.

Explanation:

Mass of seawater = 6.234 g

Mass of carbon dioxide gas  produced = 2.378 mg = 0.002378 g

1 mg = 0.001 g

Moles of carbon dioxide gas = \frac{0.002378 g}{44.009 g/mol}=5.4034\times 10^{-5} mol

1 mol of carbon dioxde gas has 1 mole pf carbon atoms,then 5.4034\times 10^{-5} mol will have ;

1\times 5.4034\times 10^{-5} mol=5.4034\times 10^{-5} mol of carbon

Mass of 5.4034\times 10^{-5} mol of carbon ;

12 g/mol\times 5.4034\times 10^{-5} mol=0.0006484 g

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

(Both the masses are in grams)

=\frac{0.0006484 g}{ 6.234 g}\times 10^6=104.01 ppm

The ppm carbon in the seawater is 104.01.

7 0
3 years ago
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