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mafiozo [28]
3 years ago
6

The chemical formula for sulfuric acid is H2SO4. In one molecule of sulfuric acid, there are _____.

Chemistry
2 answers:
a_sh-v [17]3 years ago
7 0
Four atoms of oxygen
erma4kov [3.2K]3 years ago
5 0

Answer:

four atoms of oxygen

Explanation:

two atoms of hydrogen

one sulphur atom

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Please help, once again. Can't seem to get this...
sveta [45]
In one H₂O molecule, there are two hydrogen atoms along with one oxygen atom. So for every 1 oxygen atom (of which there are 2 of in an oxygen gas molecule) there needs to be 2 hydrogen atoms per oxygen( which in the equation of 2H2 +O2–> 2H2, that 2 H2 is broken down into 4 hydrogen atoms which means 2 hydrogen atoms have to bond to 1 oxygen atom and with 4 hydrogen atoms, there will be 2 atoms of oxygen which creates 2 molecules of water.

So to solve the question,
10.5g/2=5.25g of oxygen required to fully react with hydrogen to make water
4 0
3 years ago
The molecular weight of NaCl is 58.44 grams/moles. How many grams of NaCl are found in a beaket with 100 ml of a 0.0050 M soluti
Viktor [21]

Answer:

The mass of NaCl is 0.029 grams

Explanation:

Step 1: Data given

Molecular weight of NaCl = 58.44 g/mol

Volume of solution = 100 mL = 0.100 L

Molarity = 0.0050 M

Step 2: Calculate moles NaCl

Moles NaCl = molarity * volume

Moles NaCl = 0.0050 M * 0.100 L

Moles NaCl = 0.00050 moles

Step 3: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.00050 moles * 58.44 g/mol

Mass NaCl = 0.029 grams

The mass of NaCl is 0.029 grams

4 0
3 years ago
Is a CAS number a physical or chemical property
katrin [286]
Chemical


Hope that helps
5 0
3 years ago
Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
                                                 =0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
                          =  0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16) 
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2 
∴ the emprical formula C3H8O2
           



6 0
3 years ago
What is the formula of a compound in which element y form ccp lattice and atom x occupy 1/3rd of tetrahedral voids
Kisachek [45]
Y : CCP : 4 atoms
X : tetrahedral voids would be 1/3 × 8 = 8/3

so formula would be Y12X8 or Y3X2 !!
5 0
3 years ago
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