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Veseljchak [2.6K]
2 years ago
6

The perimeter of the parallelogram below is 32.2. What equation would you set up to solve for ? What is the value of x? Select t

wo answer and round to the nearest tenth if necessary.

Mathematics
2 answers:
inessss [21]2 years ago
8 0

Answer:

ummmmmmmmmm

Step-by-step explanation:

ANTONII [103]2 years ago
4 0

Answer:

  • B and F

Step-by-step explanation:

Perimeter formula

  • P = 2(a + b)

Option B is correct for the equation

  • 3x - 8 + 16 + 3x - 8 + 16 = 32.2
  • 6x + 16 = 32.2
  • 6x = 16.2
  • x = 16.2/6
  • x = 2.7

Option F is correct for the value of x

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The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
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Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
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12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
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