So, you take the equation for y given, y=0.28x+5.92. Then you substitute the values for x in, like so:
y=0.28(2)+5.92=6.42
y=0.28(5)+5.92=7.17
y=0.28(8)+5.92=7.92
So There's your table. Next:
7.88=0.28x+5.92
x=7, so the year when admission was approximately $7.88 is year 7.
Next,
10.04=0.28x+5.92
x=<span>14.7142857143, which rounds to year 15.
I hope this helps!</span>
Answer: Option C)1 over 15 minus 1 over x equals 1 over 20
Explanation:
Since, Micah can fill a box with books in 15 minutes.
Therefore, the work done by Micah in one minute= 1/15
Also, Sydney takes the books out puts them on a shelf.
And the times taken by Micah when Sydney is also taking the books outside from the self= 20 minutes
Therefore, the work done by Micah in one minute when Sydney taking books out of the box= 1/20
Let Sydney alone takes x minutes to take books outsides the shelf.
Then, work done by Sydney in one minute=1/x
Thus, the work done by Sydney( by taking books out of the box)= the work done by Micah - work done by Micah and Sydney simultaneously= 1/15-1/20
⇒1/x=1/15-1/20
⇒1/15-1/20=1/x
⇒1/15-1/x=1/20 is the required expression.
Therefore, Option C is correct.
<u>Given</u>:
Line m is parallel to line n.
The measure of ∠1 is (4x + 15)°
The measure of ∠2 is (9x + 35)°
We need to determine the measure of ∠1
<u>Value of x:</u>
From the figure, it is obvious that ∠1 and ∠2 are linear pairs.
Thus, we have;
Substituting the measures of ∠1 and ∠2, we get;
Thus, the value of x is 10.
<u>Measure of ∠1:</u>
The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1
Thus, we have;
Thus, the measure of ∠1 is 55°
