Answer:
i = 0.00077A
Explanation:
Given:
loop radius, r = 3.0 cm = 0.03 m
Area, A = π x r² = π x 0.03² = 0.0028 m²
Magnetic Field, B = 0.75 T
Loop resistance, R = 18 Ω
time, t = 0.15 seconds
Now,
the induced emf is given as:
EMF = - BA/t .......1
Likewise,
EMF = iR.......2
Equate 1 and 2
iR = - BA/t
i = - BA/tR
i = 0.75×0.0028/0.15×18
i = 0.0021/2.7
i = 0.00077A
I recently received the following question regarding EMP effects: “What will happen to vehicles with electronic ignitions, a Chevy with an ignition module, but they are not hooked to a battery, with no path for electricity to follow, can it do damage? There may not be power on the grid, but what about a generator? Can a drill that was not plugged in still be able to run?”
The short answer is, maybe.
Let distance be x.
Time in going, t 1 = x/50
Time in coming, t 2 = x/40
Total time T = x/40 +x/50 = 9x/200
Average speed = total distance/ total time
=( x+x)/(9x/200)= 2x ×200/9x = 400/9 = 44.44 km/h
If the sun would become cooler having constant size, it would emit less ultraviolet light and less visible light than what it currently gives to earth. Hope this answers the question. Have a nice day. Thank you for posting here.
