ΔVl = L di/dt
i = i₀e -t/T
di/dt = i₀ × (-1/T) e -t/T
ΔVl = L× (-I/T i₀e -t/T
ΔVl = -L/T i₀e -t/T
b. 15mm, i₀ = 36mA, T = 1.1m
t= Os
ΔVl = 0,491V
C. t = 1ms
ΔVl = 0.198V
t = 2ms
ΔVl = 0.08V
E. t = ms
ΔVl = 0.032V
Answer:
Option 2 - Standard deviation
Explanation:
To find : Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?
Solution :
Standard deviation is defined as,
- It is a mathematical measure that is used to evaluate the difference between the mean value of a set of number and each value in the group.
- It is calculated as the square root of variance by determining the variation between each data point relative to the mean.
The measure of dispersion that indicates how much scores in a sample vary around the mean of the sample is the standard deviation.
Therefore, option 2 is correct.
The kelvin temperature/scale i think
Answer:
The right solution is "2.5 m/s²". A further explanation is given below.
Explanation:
The given values are:
Initial velocity,
= 20 m/s
Final velocity,
= 0 m/s
Time,
= 8 s
As we know,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
