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AfilCa [17]
3 years ago
5

A sphere with radius 10 cm is filled with a uniform charge distribution. The magnitude of the electric field at a point 5 cm fro

m the center of the sphere is 3014 N/coul. Use this fact to calculate the charge density rho inside the sphere.
Physics
1 answer:
Rom4ik [11]3 years ago
4 0

Answer:15 cm

Explanation: u had 10cm. them u had another 5cm

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HELP!!! I will 5 star if its helpful :(
victus00 [196]

Answer:

Net Force Formula: F1+F2+F3...+FN

*(MAKE SURE YOU MAKE NOTE OF THE NEGATIVE FORCES AND SUBTRACT THEM!)*

Explanation:

Top left: 17N+25N+25N-42N= 25N

Top right: 65N+200N-65N-150N-200N= 150N

Bottom left: 189N+123N+284N-96N-188N-312N= 0N

Bottom right: 34N+77N-12N-34N= 65N

I hope this helps! :))

5 0
3 years ago
A mechanic pushes a 2.60 ✕ 103-kg car from rest to a speed of v, doing 5,430 J of work in the process. During this time, the car
Oduvanchick [21]

Part A. We are given that a car is pushed from rest to a final speed doing 5430 Joules of work. -

To determine the final velocity we will use the work and energy theorem which states that the work done is equal to the change in kinetic energy:

W=K_f-K_0

Since the car starts from rest this means that the initial kinetic energy is zero:

W=K_f

The kinetic energy is given by:

K=\frac{1}{2}mv^2

Substituting in the formula we get:

W=\frac{1}{2}mv_f^2

Now, we solve for the final velocity. First, we multiply both sides by 2 and divide both sides by the mass:

\frac{2W}{m}=v_f^2

Now, we take the square root to both sides:

\sqrt{\frac{2W}{m}}=v_f

Now, we plug in the values:

\sqrt{\frac{2(5430J)}{2.6\times10^3kg}}=v_f

Solving the operations:

2.04\frac{m}{s}=v_f

Therefore, the final velocity is 2.04 m/s.

Part B. Now, we use the following formula for work:

W=Fd

Where "F" is the force and "d" is the distance.

Now, we set this equation equal to the work done by the force:

Fd=5430J

Now, we divide both sides by the distance "d":

F=\frac{5430J}{29m}=187.2N

Therefore, the force exerted is 187.2 Newton.

7 0
2 years ago
When the ball on the table starts moving when the table is tilted which force is used
Paladinen [302]

Answer:

gravitational pull by earth and friction  

Explanation:

When the ball is placed on tilted tale it starts rolling because of the force of gravity pulls it downward along the plane of table and frictional force produces torque which generate rotational motion as a result body will start rolling.

Push of the table will be used to generate frictional force f=μ.N

7 0
3 years ago
Before leaving her home, Myesha makes sure that every electrical appliance is unplugged and checks that every window and door is
Kryger [21]

Answer:Obsessive-Compulsive Disorder

Explanation:

Obsessive-Compulsive Disorder is a general, persistent, and soon-lasting disorder in which an individual has involuntary, repetitive thoughts and/or actions that he or she feels compelled to replicate over and over.

Myesha also shows the symptoms of OCD by constantly checking the window and doors.

An individual suffering from OCD shows symptoms like

  • Fear of or infection by germs
  • Aggressive feelings to others or self
  • Getting things in a symmetrical or optimal order  
8 0
3 years ago
Help pls!!
STatiana [176]
The correct answer would be C
5 0
3 years ago
Read 2 more answers
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