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Nadusha1986 [10]
3 years ago
13

Please help What is the magnitude of the normal force on the bag? Answer in units of N.

Physics
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

41.576 N

Explanation:

Resolving force in the inclined plane in the x and y directions gives us;

F_x = mg sin θ

F_y = mg cos θ

Thus;

F_x = 4.8 × 9.81 × sin 28

F_x = 22.106 N

F_y = 4.8 × 9.81 × cos 28

F_y = 41.576 N

We can use Newton's second law to find the normal force.. Thus;

N - F_y = 0.

Where N is normal force;

N = 41.576 N

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1. seesaw
Sergeeva-Olga [200]

Answer:

1  seesaw = first class lever

2. pencil and sharpener = wheel and axle

3. bottle opener = second class lever

4. forearm = third class lever

5. nail = wedge

Explanation:

The given objects are classic examples of simple machines.

Lever: There are 3 types of levers and they depend on where the load, applied force, and fulcrum are.

First class levers have the fulcrum in between the load and the applied force. In other words, the load and applied force are at opposite ends. The seesaw is a good example of this. Other examples would be, pliers, scissors, and the like.

Second class levers have the fulcrum and the applied force at the opposite ends. So in this case, the load is found in between. Examples of this would be a bottle opener or a crowbar.

For third class levers, the load and the fulcrum are at opposite ends and the applied force is in between. The forearm is a good example, so is a stapler, or even a broom.

A wedge is another simple machine. It is thick at one end and it gets thinner towards the other end, or it usually has a sharp end. Other examples of this would be an axe, or a knife.

A sharpener is actually a compound machine. The old-fashioned type of pencil sharpener, the one you crank makes use of a wheel and axle and a wedge. A wheel and axle is usually a machine that makes use of two circular parts; a wheel and a rod that is attached to its center.

4 0
3 years ago
A 45-year-old man is meeting his doctor for his annual physical. He suffers from Type 2 diabetes and has a family history of cor
shutvik [7]

Answer:

The man is on the verge of having a heart attack or a stroke.

Explanation:

If he has a family history of coronary (heart) disease, it means it could normally affect. Normally here means without anything aggravating it. It's already in his lineage so he could have it.

Now, he's past middle age - he's 45. He's past the growing stages of life. His organs are fully developed herefore.

Now also, he suffers from Type 2 diabetes. Although this is sometimes milder than Type 1 diabetes, it increases the risk of having a heart disease or a stroke!

Soda, especially sweetened one, is not to be taken too often because it can cause Diabetes Mellitus. For a diabetes patient, this should be a "no-go-area". Taking this constantly (everyday at work) will now put this 45-year-old man in harm's way.

He is no more at risk of having complications but already on the path to a heart disease or a stroke.

4 0
3 years ago
Where is cloud data stored?
Annette [7]

Answer: i think its local drive

Explanation:

5 0
3 years ago
Read 2 more answers
A surface completely surrounds a 3.3 × 10-6 C charge. Find the electric flux through this surface when the surface is (a) a sphe
KengaRu [80]

Answer:

Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

Explanation:

given,

surface charge (q) = 3.3 × 10⁻⁶ C

to calculate electric flux = ?

a) radius = 0.76 m

area of sphere = 4 π r²

electric flux = \dfrac{q}{\varepsilon}

\varepsilon = 8.85 \times 10^{-12} C^2/Nm^2

electric flux =  \dfrac{3.3 \times 10^{-6}}{8.85 \times 10^{-12} }

flux = 0.373 × 10 ⁶ N m²/C

electric flux in the other two cases will also be same as electric flux is independent of area

so, Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

5 0
4 years ago
A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire that has a 3.83 ×
Tju [1.3M]

Answer:

Explanation:

power of a heating element = V² / R where V is voltage and R is resistance

putting in the values

5200 = 75² / R

R = 1.082 ohm

Formula for resistance

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

1.082 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 8.29 m

b )

power of a heating element = V² / R , R is new resistance

5200 = 120² / R

R = 2.77 ohm

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

2.77 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 21.22 m

4 0
3 years ago
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