Test questions measure recall; matching concepts with their definitions measures recognition.
<u>Explanation:
</u>
According to Psychology our brain remembers everything what we learn but the understanding and remembering the right answer for the right question needs training and understanding ability. So in order to enhance the ability of recalling and recognizing among the students, the concept of test questions and matching with definitions are used in curricular activities.
As the students will be learning different terms, definitions, methods and different subjects, they should be able to distinguish among different definitions as well as they should recall the things they have learnt. So the answers for the test questions will help to recall the topics learnt by the students while the matching concept will help the students to recognize each definition with their terms.
(Example 1 )
<span>If the Voltage that furnishes the current is an ideal (no internal resistance) Voltage source. Then; </span>
<span>V/R = i </span>
<span>V/2R = i/2 If external resistance doubles, current reduced to 1/2 of original value </span>
<span>V/3R = i/3 If external resistance triples, current reduced to 1/3 of original value </span>
<span>(Example 2) </span>
<span>But if the Voltage that furnishes the current is a practical [contains an internal resistance (Ri)] Voltage source. Then the current is a function of the Voltage source`s internal resistance, which does not double nor triple, plus the external resistance which is being doubled and tripled. </span>
<span>V/(R + Ri) = i </span>
<span>V/(2R + Ri) = greater than i/2 but less than I. </span>
<span>V/(3R + Ri) = greater than i/3 but less than i/2</span>
(a) The ball’s maximum speed over the net is v(max) = √2gh.
(b) The maximum speed of the horizontally moving ball clearing the net is about 27 m/s.
(c) Speed of the ball is independent of its mass.
<h3>
Time of motion of the ball</h3>
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
1 = 0 + ¹/₂(9.8)t²
1 = 4.9t²
t² = 1/4.9
t² = 0.204
t = 0.452 s
<h3>Horizontal speed of the ball</h3>
The horizontal speed of the ball is calculated as follows;
X = vt
v = X/t
v = (12 m)/(0.452)
v = 26.6 m/s ≈ 27 m/s (proved)
<h3>Conservation of energy</h3>
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
2gh = v²
√2gh = v(max)
Speed of the ball is independent of its mass.
Learn more about horizontal velocity here: brainly.com/question/24681896
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