Molarity = (numer of mole solute) / (volume of the solution)
number of mole solute = mass solute/molar mass solute
Molarity =( mass solute/molar mass solute)/ (volume of the solution)=
= ( mass solute/((molar mass solute)*(volume of the solution))
If m is a mass of the solute, M is a molar mass a solute, V is a volume of the solution (we can think as a volume of water added).
Molarity = m/(M*V)
Answer:
3 mol Cl₂/2 mol AlCl₃ (three over two)
Step-by-step explanation:
Start with the balanced equation"
2Al + 3Cl₂⟶ 2AlCl₃
The steps in the calculation are
mass of AlCl₃ ⟶ moles of AlCl₃⟶ moles of Cl₂ ⟶ mass of Cl₂
The critical step is the <em>conversion of moles</em>.
You multiply the moles of AlCl₃ by a <em>conversion factor</em> to get moles of Al:
Moles of AlCl₃ × conversion factor = moles of Al.
The conversion factor is <em>the molar ratio</em>, and it uses the coefficients of the formulas in the balanced equation.
It is either (2 mol AlCl₃/3 mol Cl₂) or (3 mol Cl₂/2 mol AlCl₃).
You choose the one that has the desired units of the answer in the numerator.
We choose the second option, because it has the correct units.
For example,
![\text{0.2 mol AlCl}_{3} \times \frac{3\textbf{ mol Cl}_{2} }{ 2\text{ mol AlCl}_{3} } = 0.3\textbf{ mol Cl}_{2})](https://tex.z-dn.net/?f=%5Ctext%7B0.2%20mol%20AlCl%7D_%7B3%7D%20%5Ctimes%20%5Cfrac%7B3%5Ctextbf%7B%20mol%20Cl%7D_%7B2%7D%20%7D%7B%202%5Ctext%7B%20mol%20AlCl%7D_%7B3%7D%20%7D%20%3D%200.3%5Ctextbf%7B%20mol%20Cl%7D_%7B2%7D%29)
Notice how the units "mol AlCl₃" cancel and the correct units appear in the answer.
If we had used the other conversion factor, we would have gotten the wrong units.
Answer:
The most appropriate structure given the sparse spectral data is<u><em> 4-acetyl benzoic acid (see attached).</em></u>
Explanation:
It is difficult to accurately elucidate the structure of this compound without its chemical formula. But from the 1H NMR spectral data shows a total of 8 hydrogen atoms:
- 12.71 (1H. s) - confirms presence of carboxylic acid proton, C=O-OH
- 8.04 (2H, d) - confirms aromatic hydrogen
- 7.30 (2H, d) - confirms aromatic hydrogen
- 2.41 (3H,s) - confirms C=C hydrogen or ketone O=C-RCH3
The attached files show the structure and the neighboring hydrogen atoms.
<u>The most likely structure i 4-acetyl benzoic acid</u>
Answer:
Ge: [Ar] 3d10 4s2 4p2 => 6 electrons in the outer shell
Br: [Ar] 3d10 4s2 4p5 => 7 electrons in the outer shell
Kr: [Ar] 3d10 4s2 4p6 => 8 electrons in the outer shell
Explanation:
The electron affinity or propension to attract electrons is given by the electronic configuration. Remember that the most stable configuration is that were the last shell is full, i.e. it has 8 electrons.
The closer an atom is to reach the 8 electrons in the outer shell the bigger the electron affinity.
Of the three elements, Br needs only 1 electron to have 8 electrons in the outer shell, so it has the biggest electron affinity (the least negative).
Ge: needs 2 electrons to have 8 electrons in the outer shell, so it has a smaller (more negative) electron affinity than Br.
Kr, which is a noble gas, has 8 electrons and is not willing to attract more electrons at all, the it has the lowest (more negative) electron affinity of all three to the extension that really the ion is so unstable that it does not make sense to talk about a number for the electron affinity of this atom.
Read more on Brainly.com - brainly.com/question/1832586#readmore
Answer:
44.7 kWh
Explanation:
Let's consider the reduction of Al₂O₃ to Al in the Bayer process.
6 e⁻ + 3 H₂O + Al₂O₃ → 2 Al + 6 OH⁻
We can establish the following relations:
- The molar mass of Al is 26.98 g/mol.
- 2 moles of Al are produced when 6 moles of e⁻ circulate.
- 1 mol of e⁻ has a charge of 96468 c (Faraday's constant).
- 1 V = 1 J/c
- 1 kWh = 3.6 × 10⁶ J
When the applied electromotive force is 5.00 V, the energy required to produce 3.00 kg (3.00 × 10³ g) of aluminum is:
![3.00 \times 10^{3} gAl.\frac{1molAl}{26.98gAl} .\frac{6mole^{-}}{2molAl}.\frac{96468c}{1mole^{-}}.\frac{5.00J}{c}.\frac{1kWh}{3.6 \times 10^{6}J} =44.7kWh](https://tex.z-dn.net/?f=3.00%20%5Ctimes%2010%5E%7B3%7D%20gAl.%5Cfrac%7B1molAl%7D%7B26.98gAl%7D%20.%5Cfrac%7B6mole%5E%7B-%7D%7D%7B2molAl%7D.%5Cfrac%7B96468c%7D%7B1mole%5E%7B-%7D%7D.%5Cfrac%7B5.00J%7D%7Bc%7D.%5Cfrac%7B1kWh%7D%7B3.6%20%5Ctimes%2010%5E%7B6%7DJ%7D%20%3D44.7kWh)