The careers in chemistry should be closely related to working with chemical substances and the methods involved in experiments. Thus, the answers are finds practical applications information chemist and<span> market research R&D.</span>
Answer:
The new pressure is 53.3 kPa
Explanation:
This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.
T° increase → Pressure increase
T° decrease → Pressure decrease
In this case, temperature was really decreased. So the pressure must be lower.
P₁ / T₁ = P₂ / T₂
80 kPa / 300K = P₂/200K
(80 kPa / 300K) . 200 K = P₂ → 53.3 kPa
Answer:
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive ...
Explanation:
braniest
Answer:
The final volume is 3.07L
Explanation:
The general gas law will be used:
P1V1 /T1 = P2V2 /T2
V2 =P1 V1 T2 / P2 T1
Give the variables to the standard unit:
P1 = 345 torr = 345 /760 atm = 0.4539atm
T1 = -15°C = -15 + 273 = 258K
V1 = 3.48L
T2 = 36°C = 36+ 273 = 309K
P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm
V2 = ?
Equate the values into the gas equation, you have:
V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258
V2 = 488.0877 /158.8764
V2 = 3.07
The final volume is 3.07L
