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USPshnik [31]
2 years ago
8

Which of the following would be found ONLY in plant cells

Chemistry
1 answer:
marin [14]2 years ago
5 0

Answer:

chloroplasts, cell walls, or intracellular vacuoles

Explanation:

You didn't list the following, but I'm guessing it is chloroplasts, cell walls, or intracellular vacuoles

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If the reaction of 3.50 moles of lithium with excess hydrofluoric acid produced a 75.5% yield of hydrogen gas, what was the actu
melomori [17]

<u>Answer: </u>The correct answer is 1.32 mol H_2

<u>Explanation:</u>

For the reaction of lithium and hydrofluoric acid, the equation follows:

2Li+2HF\rightarrow 2LiF+H_2

By Stoichiometry of the reaction:

if 2 moles of lithium is producing 1 mole of hydrogen gas,

Then, 3.50 moles of lithium will produce = \frac{1}{2}\times 3.5=1.75mol of hydrogen gas.

  • Now, to know the theoretical yield of hydrogen gas, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ...(1)

Moles of hydrogen gas = 1.75 mol

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

1.75mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Given mass of hydrogen gas}=3.5gl

  • To calculate the percentage yield, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Percentage yield = 75.5 %

Theoretical yield = 3.5 g

Putting values in above equation, we get:

75.5=\frac{\text{actual yield}}{3.5g}\times 100\\\\\text{Actual yield}=2.64g

  • Now, calculating the moles of hydrogen gas, we put the value in equation 1, we get:

\text{Moles of hydrogen gas produced}=\frac{2.64g}{2g/mol}=1.32mol

Hence, the correct answer is 1.32 mol H_2

5 0
3 years ago
Read 2 more answers
How would you describe the rock cycle in your own words?
just olya [345]
A continuous process by which rocks are created, changed from one form to another, destroyed, and then formed again into different types of rocks. But what really know is that it's a rocky situation.
3 0
2 years ago
Calculate the freezing point of a 12.25 m 12.25m aqueous solution of propanol. Freezing point constants can be found in the list
vichka [17]

Answer:

∆t(f) = 49.755C

Explanation:

Freezing point is defined as the point in which a liquid changes from liquid to solid state. Therefore, to calculate the freezing point of aqueous solution of propanol

∆t = k × I × m

Where k is cryscopic constant =

I = vant Hoff factor = 2

M = molar concentration = 12.25m

∆t (f) = 1.9 × 12.25 × 2 = 49.755C

5 0
3 years ago
Calculate the mass of 0.00456 moles of (NH4)2SO4
Anna [14]
To find the mass you need to find the weight of a mol of the molecules by adding up the atomic mass.

N =  14.007 g/mol
H = 1.008 g/mol
S = 32.065 g/mol
O = 16 g/mol

2(14.007) + 8(1.008) + 32.065 + 4(16) = 132.143 g/mol

Now you know how much an entire mol weight you multiply it by how much you actually have 

0.00456 * 132.143 = 0.603 g
7 0
3 years ago
Which would be the best to neutralize a large acid spill in your school lab: sodium hydroxide or baking soda? Explain.
nadya68 [22]

Consider the acid spill. It is already starting to do nasty things to, say, the floor or counter. So you grab the bottle of 10% NaOH and pour some on the spill. All of a sudden, you get a great deal of heat, and you don't have any visual evidence whether your put on too little or too much. But you have added more liquid to the spill, generated more heat, and will get more damage. You have made a bigger mess, and if you added too much, you then have a neutralization problem to deal with.  

And if it is something like a strong sulfuric acid solution, adding sodium hydroxide solution will be extremely exothermic, and you could get some really nasty results.  

So now approach the spill with a handful of baking soda. You sprinkle it on the spill. It fizzes, and carbon dioxide is given off. That actually, in a very tiny way, moderates the temperature of the neutralization. And you can keep adding baking soda until the fizzing stops, and then perhaps some water to mix everything well. But what you have done is kept the volume to a minimum, added a neutralization agent that has a visible endpoint (no more gas being given off), and you don't suddenly have a huge amount of highly basic solution because you added too much.  

And what is also nice about baking soda is that you can toss some with your hand or even with a spoon, and get some distance from the spill. With a liquid, you have to get much closer

i hope this helped..

5 0
3 years ago
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