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3 years ago

PLEASE HELP ME IDENTIFY THIS ELEMENT

Chemistry

1 answer:

LiRa [457]3 years ago

5 0

Answer:

It's CO2

Explanation:

your welcome *bows*

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Hydrogen reacts with 0.771 g of carbon to form 0.90 g of a compound. What is the mass percent of hydrogen in the compound

andriy [413]

Hello!

Answer: 14.3%

Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound.

In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen.

Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.

Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.

So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%

Hope this Helps! Have A WONDERFUL Day! :)

6 0

4 years ago

Using the Bohr model, determine the lowest possible energy, in joules, for the electron in the Li2+ ion.

lyudmila [28]

Answer: E = - 19.611× $10^{-18}$ J

Explanation: The lowest possible energy can be calculated using the formula:

$E_{n} = - Z^{2}.\frac{k}{n^{2}}$

where:

Z is atomic number of the atom;

k is a constant which contains other constants and is 2.179× $10^{-18}$ J

n is a layer;

For the lowest possible, n=1.

Atom of Lithium has atomic number of Z=3

Substituing:

$E_{1} = - 3^{2}.\frac{2.179.10^{-18}}{1}$

$E_{1} =$ $-19.611.10^{-18}$ J

<u>The energy for the electron in the </u> $Li^{+2}$ <u> ion is - 19.611 joules</u>

8 0

3 years ago

When a liquid boils or evaporates to become a gas, the molecules separate into individual atoms.

Whitepunk [10]

Answer:

true

Explanation:

7 0

3 years ago

Determine the mass of 5.20 moles of C6H12

Vera_Pavlovna [14]

Hello!
We have the following data:

m (mass) = ?
n (number of moles) = 5.20 moles
MM (Molar mass of C6H12)
C = 6*12 = 72 amu
H = 12*1 = 12 amu
--------------------------
MM (Molar mass of C6H12) = 72 + 12 = 84 g/mol

Now, let's find the mass, knowing that:

$n = \dfrac{m}{MM}$

$5.20\:\:\diagup\!\!\!\!\!\!\!mol = \dfrac{m}{84\:g/\diagup\!\!\!\!\!\!\!mol}$

$m = 5.20*84$

$\boxed{\boxed{m = 436.8\:g}}\end{array}}\qquad\checkmark$

6 0

3 years ago

What is the percent by mass of magnesium sulfate in MgSO4 · 7H2O?

Degger [83]

Answer: 48.83%

Explanation: Mass percent is the ratio of mass of the particular substance to the total mass of given compound.

${\text {mass percentage}}=\frac{\text{mass of }MgSO_4}{\text {total mass}}\times 100\%$