PLEASE HELP ME IDENTIFY THIS ELEMENT

How many moles are there in 987 grams of Ra(OH)2? id also love to know the simplest equation for converting moles --> so i co

OlgaM077 [116]

Mole = $\frac{mass}{molar mass}$

Mass of Radium Hydroxide = 987g
Molar Mass of $Ra(OH) _{2}$ = ((226) + (2 * 16) + (2 * 1))
= 260 g / mol

∴ Moles of <span> $Ra(OH) _{2}$ = </span> $\frac{987 g }{ 260 g / mol }$
= 3.796 mols

6 0

2 years ago

Which of the following models represents an atom that is more reactive than the

Zanzabum

Answer:

Model A

Explanation:

Model A represents an atom that is more reactive than the others represented.

Valence electrons actually determine the reactivity of elements. They also determine the properties of elements.

Elements with one valence electron are highly reactive because they need low energy to remove them. They can either gain more electrons to become stable or they share/give out their electrons.

Therefore, Model A is the correct answer because it has one valence electron and its valence electron is farther from the nucleus thereby this makes it more reactive.

8 0

3 years ago

Write a balanced chemical equation for the reaction of magnesium with hydrochloric acid (HCI (aq) to form Magnesium chloride and

ivann1987 [24]

Mg (s) + HCl (aq) → MgCl₂(s) + H₂(g)

Looking at the equation :

We have 1 Mg at the left hand side and 1 Mg as well on the right hand side.
So that is balanced.

We have 1 H at the left hand side and 2 H on the right hand side.
So that is not balanced. Same for Chlorine. Cl.

We add 2 to the HCl on the left hand side and that balances it.

Mg(s) + 2HCl(aq) → MgCl₂(s) + H₂(g)

6 0

2 years ago

Read 2 more answers

The solubility of BaCO3(s) in water at a certain temperature is 4.4 10–5 mol/L. Calculate the value of Ksp for BaCO3(s) at this

azamat

Answer : The value of $K_{sp}$ for $BaCO_3$ is $19.36\times 10^{-10}mole^2/L^2$ .

Solution : Given,

Solubility of $BaCO_3$ in water = $4.4\times 10^{-5}mole/L$

The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.

The equilibrium equation is,

$BaCO_3\rightleftharpoons Ba^{2+}+CO^{2-}_3$