The idea that atoms are neither gained nor lost during a chemical reaction is called the law of

Match the set of measurements of the boiling point of water with the best

Mashcka [7]

Answer:

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Explanation:

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6 0

3 years ago

At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?

rjkz [21]

E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. Relative rates of effusion is related to the molecular mass.
a) M(N₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, CO and N₂ have iexact molecular masses and will effuse at nearly identical rates.

8 0

3 years ago

26.8 moles of argon contain how many atoms?

Maru [420]

1.61 × 1023 Multiply by 26.8 to get the answer.161.33 x 10 ^23

4 0

3 years ago

Read 2 more answers

Calculate the molecular weight of a substance. In which the solution of this substance in the water has a concentration of 7 per

Eduardwww [97]

Answer : The molecular weight of a substance is 157.3 g/mol

Explanation :

As we are given that 7 % by weight that means 7 grams of solute present in 100 grams of solution.

Mass of solute = 7 g

Mass of solution = 100 g

Mass of solvent = 100 - 7 = 93 g

Formula used :

$\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=k_f\times\frac{\text{Mass of substance(solute)}\times 1000}{\text{Molar mass of substance(solute)}\times \text{Mass of water(solvent)}}$

where,

$\Delta T_f$ = change in freezing point

$T_f^o$ = temperature of pure water = $0^oC$

$T_f$ = temperature of solution = $-0.89^oC$

$K_f$ = freezing point constant of water = $1.86^oC/m$

m = molality

Now put all the given values in this formula, we get

$(0-(-0.89))^oC=1.86^oC/m\times \frac{7g\times 1000}{\text{Molar mass of substance(solute)}\times 93g}$

$\text{Molar mass of substance(solute)}=157.3g/mol$

Therefore, the molecular weight of a substance is 157.3 g/mol

7 0

3 years ago

A cat travels 240 meters in 30 seconds, and a sprinter travels 100 meters in 9.5 seconds. Which is traveling faster, the cat or

joja [24]

Answer:

The cat

Explanation:

1) You need to find how many meters per second each thing is sprinting, so you can divide the meters by seconds for each.

$\frac{240}{30} = 8 m/s\\\frac{100}{9.5} = around 10.5 m/s$

2) Per second, the sprinter is able to achieve 8 meters, while the cat can do around 10.5 meters. 10.5 is greater than 8, making the cat faster than the sprinter.

4 0

2 years ago