Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Answer:
6400
Step-by-step explanation:
6400/80=80
80+13=93
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Answer:
I hope it helps u
Step-by-step explanation:
Let's solve your system by elimination.
15j+12k=18;5j+4k=6
Multiply the second equation by -3, then add the equations together.
(15j+12k=18)
−3(5j+4k=6)
Becomes:
15j+12k=18
−15j−12k=−18
Add these equations to eliminate j:
0=0
Answer:
Infinitely many solutions
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Answer:
14/21
Step-by-step explanation:
14/21 is divisible by 7, and can reduce to 2/3
By the graph of a straight line through the origin with a slope equal to the unit rate
