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ASHA 777 [7]
3 years ago
6

If (2i/2+i)-(3i/3+i)=a+bi, then b=

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

b = -1/10.

Step-by-step explanation:

(2i/2+i)-(3i/3+i)

= 2i(3 + i) - 3i(2 + i) / (2 + i)(3 + i)

= 6i + 2i^2 - 6i - 3i^2 / (2 + i)(3 + i)

=  (-2 + 3) / (6 + 5i - 1)

= 1 / (5 + 5i)

Now we multiply top and bottom by 5 - 5i :

= 5 - 5i / (5 + 5i)(5 - 5i)

=  5 - 5i / 25 -25i^2

= 5 - 5i / 50

= 1/10 - 1/10i

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geniusboy [140]
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4 0
3 years ago
Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco
ANTONII [103]

Answer:

(a) The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable <em>X</em> is defined as the flight time between the two cities.

Since the random variable <em>X</em> denotes time interval, the random variable <em>X</em> is continuous.

(a)

The random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 10 minutes and <em>b</em> = 154 minutes.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

                           = P (128.50 < X < 146.50)

                           =\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx

                           =\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx

                           =\frac{1}{52}\times (146.50-128.50)

                           =0.3462

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. <em>X</em> ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

                 = P (X > 131.50)

                 =\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx

                 =\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx

                 =\frac{1}{52}\times (154-131.50)

                 =0.4327

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

6 0
3 years ago
Need the answer asap!!!​
aalyn [17]

Answer:

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Step-by-step explanation:

b-6a+12b-6a+5

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3 years ago
On a scale 1/5 drawing of a car, one part is 8 inches long. How long will the actual car part be?
aivan3 [116]
8x5=40
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What does this math problem mean |3x|=9
Vladimir79 [104]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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