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Nikolay [14]
3 years ago
12

Find five consecutive integers such that the sum of the first and 5 times the third is equal to 41 less than 3 times the sum of

the second fourth and fifth
Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

We'll cal the first integer x and then the rest of them will be x + 1, x + 2, x + 3 and x + 4. We can write x + 5(x + 2) = 3(x + 1 + x + 3 + x + 4) - 41.

x + 5x + 10 = 3(3x + 8) - 41

6x + 10 = 9x + 24 - 41

6x + 10 = 9x - 17

3x = 27

x = 9

The numbers are 9, 10, 11, 12, 13.

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Which of the following ratios is not equivalent to the other three 2/3 4to6 8to12 4/5
balu736 [363]

Answer:

The non-equivalent ratio is 4:5.

Step-by-step explanation:

2/3 4/6 and 8/12 are equivalent because they are all multiples of each other.

7 0
3 years ago
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Step-by-step explanation:

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4 years ago
What are possible coordinates of point F if triangle DEF is<br> congruent to triangle ABC?
Lemur [1.5K]

Answer:

(-1, 4)

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Hope this helps!

8 0
3 years ago
a man has been driving a second hand car for the past four years. over these four years he managed to save 16% as a deposit of t
Ksenya-84 [330]

Answer:

$120,000

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Given that

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7 0
3 years ago
Plss help I have been asking for help since no one has helped me plss this has been due for a long time plss help me :(
Arturiano [62]

Step-by-step explanation:

hi I am Cynthia am in form one at lugulu girls high school here in Kenya. 1 in that question write x to be one of your consecutive numbers because you don't know the actual number okay?then go to x+1,x+2,x+3.since they were 4 consecutive numbers you already written them down so you need to equate like this x+x+1+x+2+x+3=52 so from there you can continue so any questions just let me know okay?

5 0
4 years ago
Read 2 more answers
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