Find five consecutive integers such that the sum of the first and 5 times the third is equal to 41 less than 3 times the sum of
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PART A
The geometric sequence is defined by the equation
To find the first three terms, we put n=1,2,3
When n=1,
When n=2,
When n=3
The first three terms are,
PART B
The common ratio can be found using any two consecutive terms.
The common ratio is given by,
PART C
To find
We substitute n=11 into the equation of the geometric sequence.
This implies that,
The geometric sequence is defined by the equation
To find the first three terms, we put n=1,2,3
When n=1,
When n=2,
When n=3
The first three terms are,
PART B
The common ratio can be found using any two consecutive terms.
The common ratio is given by,
PART C
To find
We substitute n=11 into the equation of the geometric sequence.
This implies that,