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3 years ago

PLEASE HELP ME ASAP The trapezoid shown is isosceles and MN is a mid segment.

Mathematics

1 answer:

Vikentia [17]3 years ago

6 0

Answer:

The measurement of x is 106° and the measurement of y is 74°.

Step-by-step explanation:

The definition of an isosceles trapezoid is a trapezoid that has two pairs of congruent base angles. One pair at the top and the other pair at the bottom.

When you look at the trapezoid, you are given an angle. This angle measures 74°. Since base angles are congruent in an isosceles trapezoid, then the measurement of y is also 74°.

Another thing about isosceles trapezoids and all trapezoids is that they all have an interior angles sum of 360°. Interior means all of the angles inside the shape. So, since we know the bottom base angles both have a measurement of 74°, then we can add these angles together.

74 + 74 = 148

Now, we subtract 148 from 360 so we can find the measurement of x.

360 - 148 = 212

Now since there are two top base angles, then we will divide 2 from 212.

212 ÷ 2 = 106

So, the measurement of x is 106°.

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A research center claims that at least 4545% of adults in a certain country think the government is not aggressive enough in pu

frez [133]

Answer:

$z=\frac{0.39 -0.45}{\sqrt{\frac{0.45(1-0.45)}{700}}}=-3.19$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interst is significantly lower than 0.45 and the claim is not appropiate

Step-by-step explanation:

Data given and notation

n=700 represent the random sample taken

$\hat p=0.39$ estimated proportion of interest

$p_o=0.7$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is at least 0.45.:

Null hypothesis: $p\geq 0.45$

Alternative hypothesis: $p < 0.45$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.39 -0.45}{\sqrt{\frac{0.45(1-0.45)}{700}}}=-3.19$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a lef tailed test the p value would be:

$p_v =P(z$

3 0

4 years ago

There are 13 bagels in a baker's dozen. Hillary,Mark, and Tam share the bagels equally. Will each friend get more than or fewer

vaieri [72.5K]

Answer:

Each friend will get more than 4 whole bagels.

Step-by-step explanation:

First off, although the question asks for 13 bagels divided between 3 friends, let's use a number that results in a whole number when divided by 3, but is close to 13.

This number can be 12.

12 divided by 3 is 4, so each friend gets 4 bagels if there are a total of 12 bagels.

However, there are more than 12 bagels so we know that each of the the 3 friends will get more than 4 bagels each.

4 0

4 years ago

A poll found that 58% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.

Radda [10]

Answer: (53.49%, 62.51%)

Step-by-step explanation:

Given : A poll found that 58% of U.S. adult Twitter users get at least some news on Twitter.

i.e. p= 0.58

The standard error for this estimate was 2.3%

i.e. S.E.=0.023

Critical value for 95% confidence : $z_{\alpha/2}=1.96$

Confidence interval : $p\pm z_{\alpha/2}(S.E.)$

i.e. $0.58\pm (1.96)(0.023)$

$=0.58\pm 0.04508=(0.58-0.04508,\ 0.58+0.04508)\\\\=(0.53492,\ 0.62508)=(53.492\%,\ 62.508\%)=(53.49\%,\ 62.51\%)$

Conclusion : We are 95% confident that the true population proportion of U.S. adult Twitter users who get some news on Twitter falls in interval (53.49%, 62.51%)

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4 years ago

6^8/6 with a single positive exponent.

Andre45 [30]

I think I know this but I need a picture of it

6 0

3 years ago

Read 2 more answers

Can someone help? Explain and give work in how you got the answer.

kvasek [131]

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