All categories

3 years ago

A spinner is spun four times. What is the probability that the spinner lands on 2 each time?

Mathematics

1 answer:

xenn [34]3 years ago

6 0

Answer:

personally,

Step-by-step explanation:

I would say d :)

You might be interested in

The table shows values for the two functions fand

wlad13 [49]

First find g(0). g(0) is -1. Now find f(-1). f(-1) will be 1. So your answer is C.

6 0

3 years ago

Nilai x yang memenuhi persamaan linier dari 2x-7/2=3-6-5x/6 adalah

emmainna [20.7K]

2x-7/2 = 3-6-5x/6
⇒ 2x+ 5x/6= -3+ 7/2
⇒ 2 5/6x= 1/2
⇒ x= (1/2)/ (2 5/6)
⇒ x= 3/17

The final answer is x= 3/17~

5 0

4 years ago

An artist is constructing a piece of art in the shape of rectangle. The artist wants to use string to tightly tie each vertex of

Liula [17]

Answer:

65.8 ft

Step-by-step explanation:

The number of strings required to tie each vertex to the other three will be ...

(4)(3)/2 = 6

Those strings will be perimeter strings plus two diagonal strings. The lengths of the perimeter strings are given as 12 ft and 7 ft. The lengths of the diagonal strings can be found using the Pythagorean theorem.

d² = 12² +7² = 144 +49 = 193

d = √193 ≈ 13.892

Then the total length of all strings is ...

L = 2(12.0 +7.0 +13.9) = 65.8 . . . . feet

The artist will need 65.8 feet of string.

4 0

3 years ago

Which property is represented by the number sentence shown below?

Murljashka [212]

Associative property of addition.

This means that no matter where you put the parenthesis, you will get the same solution.

Hope this helps!

5 0

4 years ago

Read 2 more answers

Q.04: (11 points) Given the polar curve r = e θ , where 0 ≤ θ ≤ 2π. Find points on the curve in the form (r, θ) where there is a

Citrus2011 [14]

I suppose the curve is $r(\theta)=e^\theta$ .

Tangent lines to the curve have slope $\frac{dy}{dx}$ ; use the chain rule to get this in polar coordinates.

$\dfrac{dy}{dx}=\dfrac{dy}{d\theta}\dfrac{d\theta}{dx}=\dfrac{\frac{dy}{d\theta}}{\frac{dx}{d\theta}}$

We have

$y(\theta)=r(\theta)\sin\theta\implies\dfrac{dy}{d\theta}=\dfrac{dr}{d\theta}\sin\theta+r(\theta)\cos\theta$

$x(\theta)=r(\theta)\cos\theta\implies\dfrac{dx}{d\theta}=\dfrac{dr}{d\theta}\cos\theta-r(\theta)\sin\theta$

$r(\theta)=e^\theta\implies\dfrac{dr}{d\theta}=e^\theta$

$\implies\dfrac{dy}{dx}=\dfrac{e^\theta\sin\theta+e^\theta\cos\theta}{e^\theta\cos\theta-e^\theta\sin\theta}=\dfrac{\sin\theta+\cos\theta}{\cos\theta-\sin\theta}$