<span> resistivity Ag 15.9e-9 Ω-m
resistivity Fe 100e-9 Ω-m
temperature coefficient of resistivity
α = 0.0038/ºC Ag
R = R₀(1 + α∆T)
4*100 = 15.9(1 + (0.0038)∆T)
400/15.9 = 25 = 1 + (0.0038)∆T
(0.0038)∆T = 24
∆T = 6357ºC
add 25º to get 6382ºC </span>
<span> I believe</span>
Answer:
0.04895m
Explanation:
Given magnetic field , Length of wire , current and , the diameter, of the coil is calculated as:
Hence, the diameter of the coil is 0.04895m
Answer:
(C) HBr is an acid .......
Answer:C
Explanation:
Radar waves will be useful to examine the surface of the planet.
Radio waves are the shorter wavelength microwaves ranging approximately 1 cm.
Short wavelength causes large reflection from large objects. These waves are useful to detect smaller objects like water drops in the cloud.
They can penetrate clouds and that is why they are used in weather forecasting, air traffic control, etc.
Answer:
q = 2 10⁻⁸ C
Explanation:
For this exercise we use the translational equilibrium equation
F_e -A =
F_e = W
the electric force is given by Coulomb's law
F_e =
in this case they indicate that the loads on the tapes are equal
F_e = k q² / r²
we substitute
k q² / r² = m g
q =
calculate
q =
q =
q = 1,999 10⁻⁸ C
q = 2 10⁻⁸ C