Answer:
See the explanation below
Explanation:
This problem can be better understood graphically, so in the attached image we will use a diagram of a positive displacement air pump.
We can see that when she pushes the plunger, we see that the volume decreases.
Answer:
1) joule
2)
3)
Explanation:
1) Luminosity is the <u>amount of light emitted</u> (measured in Joule) by an object in a unit of<u> time</u> (measured in seconds). Hence in SI units luminosity is expressed as joules per second (), which is equal to Watts (
).
This amount of light emitted is also called radiated electromagnetic power, and when this is measured in relation with time, the result is also called radiant power emitted by a light-emitting object.
Therefore, if we want to calculate luminosity the Joule as a unit will be used.
2) Work is expressed as force
multiplied by the distane
:
Where force has units of and distance units of
.
If we input the units we will have:
This is 1Joule (
) in the SI system, which is also equal to
3) The formula to calculate the percent error is:
Where:
is the experimental value
is the accepted value
This is the percent error