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3 years ago

You are instructed to remove the appendicular skeleton of a cadaver. To accomplish this goal, you would

1 answer:

6 0

An appendicular skeleton includes appendages to the central skeleton and the bones of the upper and lower limbs, including the girdles that attach them to the axial skeleton. The upper limbs include shoulder, arms, forearm, and hand.The appendicular skeleton is primarily concerned with the Movement.

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A particle with charge −5 µC is located on

Nataly [62]

Answer:

36.25 N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=9\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the magnitude of the two charges

r is the separation between the two charges

Moreover:

- The force is repulsive if the two charges have same sign

- The force is attractive if the two charges have opposite sign

In this problem, we have 3 charges:

$q_1=-5\mu C = -5\cdot 10^{-6}C$ is the charge located at $x=+10 cm = +0.10 m$

$q_2=+6\mu C=+6\cdot 10^{-6}C$ is the charge located at $x=-8 cm =-0.08 m$

$q_3=+2\mu C=+2\cdot 10^{-6}C$ is the charge located at $x=-2 cm=-0.02 m$

The force between charge 1 and charge 3 is:

$F_{13}=\frac{kq_1 q_3}{(x_1-x_3)^2}=\frac{(9\cdot 10^9)(5\cdot 10^{-6})(2\cdot 10^{-6})}{(0.10-(-0.02))^2}=6.25 N$

And since the two charges have opposite sign, the force is attractive, so the force on charge 3 is to the right (towards charge 1).

The force between charge 2 and charge 3 is:

$F_{23}=\frac{kq_2 q_3}{(x_2-x_3)^2}=\frac{(9\cdot 10^9)(6\cdot 10^{-6})(2\cdot 10^{-6})}{(-0.08-(-0.02))^2}=30.0 N$

And since the two charges have same sign, the force is repulsive, so the force on charge 3 is to the right (away from charge 2).

So the two forces on charge 3 have same direction (to the right), so the net force is the sum of the two forces:

$F=F_{13}+F_{23}=6.25+30.0=36.25 N$

8 0

4 years ago

Two asteroids with masses 3.45 x 103 kg and 6.06 x 104 kg are separated by

alexgriva [62]

Answer:

Explanation

ap3x

4 0

3 years ago

Read 2 more answers

While punting a football, a kicker rotates his leg about the hip joint. the moment of inertia of the leg is 3.75 kg m2 and its r

otez555 [7]

Angular velocity is the rate of the change of angular displacement of a body that is in a circular motion. It is a vector quantity so it consists of a magnitude and direction. It is equal to the linear velocity divided by the radius of the circular motion. However, we are not given the linear velocity and the radius of the motion. We instead use the equation for the rotational kinetic energy. It is expressed as:

Rotational kinetic energy = Iω^2 / 2

where I is the inertia and ω is the angular velocity

175 = (3.75)ω^2 / 2
ω = 9.66 rad/s

The angular velocity of the motion is about 9.66 rad / s.

7 0

4 years ago

Read 2 more answers

A series ac circuit contains a 250-Ω resistor, a 15-mH inductor, a 3.5-μF capacitor, and an ac power source of voltage amplitude

Genrish500 [490]

Answer:

Explanation:

power factor in a series AC circuit (cosΘ) = $\frac{R}{Z}$

R = resistance

Z = impedance of the circuit

Z²= R² + (XL - XC)²

XL = wL

from the question w is the angular frequency = 360 rad/s

360× 15× 10⁻³

= 5.4Ω

XC = $\frac{1}{wc}$

= $\frac{1}{360 * 3.5 * 10-6}$

= 793.65Ω

Z²= 250² + (5.4 - 793.65)²

= 62500 + (-788.25)²

62500+621338.06

Z²= 683838.0625

Z =√ 683838.0625

Z= 826. 95Ω

(a) power factor = R / Z

= 250 / 826.95

= 0.30

b) average power delivered to the entire circuit.

V = I × Z

I = $\frac{V}{Z} = \frac{45}{826.95}$

I =0.054A

P = I× V

= 0.054× 45

= 2.43 W

c) average power delivered to the resistor

P = I²× R

= 0.054²× 250

= 0.729 W

average power delivered to the capacitor

P = I² ×XC

=0.054²× 793.65

= 2.31 W

average power delivered to the inductor

P = I²× XL

= 0.054²× 5.4

= 0.02W

6 0

3 years ago

Define gravitational field

MariettaO [177]

"the field of force surrounding a body of finite mass in which anotherbody would experience an attractive force that is proportional to theproduct of the masses and inversely proportional to the square of thedistance between them."

4 0

3 years ago